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cupoosta [38]
3 years ago
11

y varies inversely x and y =-4 when x =7 . find the constant of variation and use it to write the equation that relates the vari

ables
Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0
When y varies inversely with x, we have the follow equation:

y = kx

k = constant of variation

To find k, plugin the values for y = -4 and x = 7 and then solve for k

y = kx
-4 = k7
-4 / 7 = k7/7
-4 / 7 = k
k = -4 / 7
Now that we found k, we write the equation that relates the variables like below
y = -\frac{4}{7}x
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Mr.Jones has a new car. The manufacturer says that the car should get about 28 miles per gallon in the city. About how many mile
Elza [17]

Answer:

73

Step-by-step explanation:

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8 0
3 years ago
Is 42 a factor of 6?
Wewaii [24]
I hope this helps you


42=1.42

42= 2.3.7

42= 6.7
3 0
3 years ago
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Pls help i am on a timer
stich3 [128]

Answer:

x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

x^2 +  (-1)^2 = 1 + (-1)^2

(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\

⇒ take the square root of both sides;

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Therefore, option B is the right solution.

3 0
2 years ago
Mei does 6 problems in 18 minutes. How many can she complete in 12 minutes
Dmitriy789 [7]
Do cross multiplication

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 18    12

Now cross multiply

(6)(12) = (18)(x)

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Divide both sides by 18
     
    
     <u>72</u>  = <u>18x</u>
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5 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1
Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

Step-by-step explanation:

Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

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