The scale factor of dilation from AB to EF is 0.25
<h3>How to determine the scale factor of dilation?</h3>
The given parameters are:
- EFJL is dilation of ABIK
- AB has a length of 12
- EF has a length of 3
From the above parameters, side lengths AB and EF are corresponding sides
This means that:
The scale factor of dilation (k) is
k = AB/EF
So, we have
k = 3/12
Evaluate
k = 0.25
Hence, the scale factor of dilation from AB to EF is 0.25
Read more about scale factors at:
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N=3 darling . N is being times by 3. So 3*3=9 and minus one is 8!
60(one hour) divided by 15 is 4. 4 tines 18 is 112. A postal service person can deliver 112 pieces in 1 hour. Hope this helps!
Answer:
The lower limit of the 90% confidence interval for the population mean life of the new model is 72.53 months.
Step-by-step explanation:
Our sample size is 13.
The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

Then, we need to subtract one by the confidence level
and divide by 2. So:

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 12 and 0.05 in the t-distribution table, we have
.
Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

Now, we multiply T and s

The lower end of the interval is the mean subtracted by M. So it is 75 - 2.47 = 72.53
The lower limit of the 90% confidence interval for the population mean life of the new model is 72.53 months.