Answer:
Algebraic expression ; 3x = 39
Step-by-step explanation:
Let the unknown number be x
Further solving
I believe the length of Paul's model is C, 13/6 feet
Answer:
The population in 2003 was 234 million
Step-by-step explanation:
In order to calculate the population in 2003 we would have to use the The exponential growth formula as follows:
p(y)=ir^t
According to the given data:
p(y)=233 million
i=231 million
t
=1999-1991
Therefore, 233 million=231 million r^(1999-1991)
(233 million/231 million)^(1/8)=r
p(y)=231 million(233 million/231 million)^((y-1991)/8)
Therefore, in 2003
p(2003)=231 million(233 million/231 million)^((2003-1991)/8)
p(2003)=231 million(233 million/231 million)^(1.5)
p(2003)=234 million
The population in 2003 was 234 million
Multiply the numerator and denominator by the same number.<span> Two fractions that are different but equivalent have, by definition, numerators and denominators that are multiples of each other. In other words, multiplying the numerator and denominator of a </span>fraction<span> by the same number will produce an equivalent fraction. Though the numbers in the new fraction will be different, the fractions will have the same value.</span><span>For instance, if we take the fraction 4/8 and multiply both the numerator and denominator by 2, we get (4×2)/(8×2) = 8/16. These two fractions are equivalent.(4×2)/(8×2) is essentially the same as 4/8 × 2/2 Remember that when multiplying two fractions, we multiply across, meaning numerator to numerator and denominator to denominator.Notice that 2/2 equals 1 when you carry out the division. Thus, it's easy to see why 4/8 and 8/16 are equivalent since multiplying 4/8 × (2/2) = 4/8 still. The same way it’s fair to say that 4/8 = 8/16.<span>Any given fraction has an infinite number of equivalent fractions. You can multiply the numerator and denominator by any whole number, no matter how large or small to obtain an equivalent fraction.</span></span>
Answer:
LN and NK
Step-by-step explanation:
A perpendicular bisector of a line segment divides the line segment into 2 equal halves.
Here, line JM is a perpendicular bisector of line segment LK at point N. So, line JM divides the line segment LK into 2 equal halves.
The two equal halves are segment LN and segment NK.
Therefore, segment LN is congruent to segment NK.
