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andrew-mc [135]
3 years ago
13

The countries population in 1991 was 231 million . In 1999 it’s was 233 million. estimate the population in 2003 used The expone

ntial growth formula. Round your answer to the nearest million
Mathematics
1 answer:
liraira [26]3 years ago
7 0

Answer:

The population in 2003 was 234  million

Step-by-step explanation:

In order to calculate the population in 2003 we would have to use the The exponential growth formula as follows:

p(y)=ir^t

According to the given data:

p(y)=233 million

i=231 million

t =1999-1991

Therefore, 233 million=231 million r^(1999-1991)

(233 million/231 million)^(1/8)=r

p(y)=231 million(233 million/231 million)^((y-1991)/8)  

Therefore, in 2003   p(2003)=231 million(233 million/231 million)^((2003-1991)/8)

p(2003)=231 million(233 million/231 million)^(1.5)

p(2003)=234  million

The population in 2003 was 234  million

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1. Simplify. 5–1(3–2)
konstantin123 [22]

Answer with explanation:

Using following law of indices

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9. (4\times x\times y^2)^3\times (xy)^5=4^3\times x^3\times (y^2)^3\times x^5 \times y^5\\\\=64\times x^{3+5}\times y^{5+6}\\\\=64x^8y^{11}\\\\10.(2\times t^3)^3(0.4\times r)^2=2^3 \times (t^3)^3\times (0.4)^2 \times r^2=8\times t^9 \times 0.16 \times r^2=1.28r^2t^9

8. A number raised to a negative exponent is negative.

Explaining with the help of few examples

 1.2^{-3}=\frac{1}{2^3}=\frac{1}{8}\\\\ 2.(-3)^{-3}=\frac{1}{(-3)^{3}}=\frac{-1}{27}

Option C: Sometimes

1.Option B

2.Option A

3.Option C

4.Option A

5.Option D

6.  81 \times 10^6

7.Option B

8.Option C

9.Option A

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