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andrew-mc [135]
3 years ago
13

The countries population in 1991 was 231 million . In 1999 it’s was 233 million. estimate the population in 2003 used The expone

ntial growth formula. Round your answer to the nearest million
Mathematics
1 answer:
liraira [26]3 years ago
7 0

Answer:

The population in 2003 was 234  million

Step-by-step explanation:

In order to calculate the population in 2003 we would have to use the The exponential growth formula as follows:

p(y)=ir^t

According to the given data:

p(y)=233 million

i=231 million

t =1999-1991

Therefore, 233 million=231 million r^(1999-1991)

(233 million/231 million)^(1/8)=r

p(y)=231 million(233 million/231 million)^((y-1991)/8)  

Therefore, in 2003   p(2003)=231 million(233 million/231 million)^((2003-1991)/8)

p(2003)=231 million(233 million/231 million)^(1.5)

p(2003)=234  million

The population in 2003 was 234  million

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Look at the pair of equivalent expressions. 36 + 8 = ?(9 + 2) What number is missing from the expression?
JulijaS [17]

Answer:

? = 4

4 is the number missing on the right.

Step-by-step explanation:

Check out the 8 on left. It has become a 2 on the right. How did that happen?

What do you have to multiply the 2 by to get 8?

Before I answer, check out the 9 on the right. What did you have to multiply it by to get 36? The answer to that is 4 isn't it?

What about the 2. Don't you have to multiply it by 4 to get 8?

36 + 8 = 4(9 + 2) The distributive property on the right will produce the numbers on the left.

So ? = 4

7 0
3 years ago
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ANEK [815]

All you have to do is plug in the number for x, and find y. I will write this out as if in that chart you have shown.

x                            y = 9 - 3x                                    y

_______________________________________

0                           y = 9 - 3(0)                                  9

1                            y = 9 - 3(1)                                   6

2                           y = 9 - 3(2)                                  3

3                           y = 9 - 3(3)                                  0


Hope that helps!!


4 0
3 years ago
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8+12y+6y^2+6y^3+8y+4y^2+y^3\\=8+(12y+8y)+(6y^2+4y^2)+(6y^3+y^3)\\=8+20y+10y^2+7y^3



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Answer:

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