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andrew-mc [135]
4 years ago
13

The countries population in 1991 was 231 million . In 1999 it’s was 233 million. estimate the population in 2003 used The expone

ntial growth formula. Round your answer to the nearest million
Mathematics
1 answer:
liraira [26]4 years ago
7 0

Answer:

The population in 2003 was 234  million

Step-by-step explanation:

In order to calculate the population in 2003 we would have to use the The exponential growth formula as follows:

p(y)=ir^t

According to the given data:

p(y)=233 million

i=231 million

t =1999-1991

Therefore, 233 million=231 million r^(1999-1991)

(233 million/231 million)^(1/8)=r

p(y)=231 million(233 million/231 million)^((y-1991)/8)  

Therefore, in 2003   p(2003)=231 million(233 million/231 million)^((2003-1991)/8)

p(2003)=231 million(233 million/231 million)^(1.5)

p(2003)=234  million

The population in 2003 was 234  million

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Step-by-step explanation:

Considering the expression

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Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

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so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

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so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

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\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

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\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

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Therefore

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