Answer:
537 students
11 days
Step-by-step explanation:
5000
y= -----------------
(1+4999e^-0.8t)
a) after 8 days means t =8
5000
y= -----------------
(1+4999e^-0.8*8)
5000
y= -----------------
(1+4999e^-6.4)
5000
y= -----------------
(1+8.306)
5000
y= -----------------
(9.306)
y =537.28
Rounding to the nearest student
y = 537 students
b) 1/2 the student population means y =2500 (The 5000 is the student population)
5000
2500= -----------------
(1+4999e^-0.8t)
Multiply each side by (1+4999e^-0.8t)
2500 (1+4999e^-0.8t) = 5000
Divide each side by 2500
(1+4999e^-0.8t) = 5000/2500
(1+4999e^-0.8t) = 2
Subtract 1
(4999e^-0.8t) = 2-1
(4999e^-0.8t)=1
Divide by 4999
(4999/4999e^-0.8t)=1/4999
e^-0.8t=1/4999
Take the natural log of each side
ln(e^-0.8t)=ln(1/4999)
-.8t = ln(1/4999)
Divide by -.8
-.8/-8t = -1/.8 *ln(1/4999)
t = -1/.8 *ln(1/4999)
t≈10.6462
Rounding, it will take 11 days
A square has the same width and height, so find the gcd of 90 and 126. Here are there factors:
90:1,2,3,5,9,10,15,18,30,45,90
126:2,3,6, 7,9,14,18,21,42,63,126
18 is the largest in both so the number of squares will be
90/18 * 126/18
= 5*7 = 35
Let, Jason = J and M = Megan
M = J(1 + 1/4)
So putting 6 where J is and solving:
<em>M = 6(1 + 1/4)
</em><em>M= 7.5</em>
When Jason runs 6 miles Megan runs 7.5
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Answer:
A, B, C, and E.
Step-by-step explanation:
I don’t know how to explain what I did very well.
