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stepladder [879]
3 years ago
13

The table below shows the number of marbles of different colors in a bag:

Mathematics
2 answers:
Butoxors [25]3 years ago
8 0

Answer:

It is the first option

Step-by-step explanation:

noname [10]3 years ago
3 0
There are a total of 5+8+2=15 marbles.  There's a 5/15 chance of drawing a red marble in the first trial.  Then, there are 4 red marbles and 14 total marbles left, so afterwards, there's a probability of 4/14 that the second marble is red.  The probability overall is found by multiplying these together, so the first answer is the best.

There are 2+6+7=15 cakes.  There's a 6/15 chance that the first cake selected will be a pineapple cake, and then a 2/14 chance that the second cake selected will be a strawberry cake, by the same logic as above.  This is equal to 12/210.  The first answer is the best option.
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Something x (-2) = 70
bija089 [108]

Answer:

The answer is x = -35

7 0
3 years ago
I need help with this (simplify 8^3)
sattari [20]

Answer:

512

Step-by-step explanation:

8 = 2^3

Therefore,

8^3  

= (2^3)^3

= 2^(3*3)

= 2^9

= 512

Thus, 8^3 = 512

<h2>Please mark my answer as Brainliest!!!</h2>
5 0
3 years ago
Read 2 more answers
(Will mark brainest)If it rains tomorrow the probability is 0.6 that James will practice piano. if it doesn't rain tomorrow ther
sergiy2304 [10]

Answer:

0.64

Step-by-step explanation:

P(J / R) = P (J and R) / P(R) 

0.8 = P (J and R) / 0.6 

P (J and R) = 0.6 * 0.8 = 0.48 [Probability John practicing and it is raining] 

P(J / NR) = P (J and NR) / P(NR) 

0.4 = P (J and NR) / (1 - 0.6) = P (J and NR) / 0.4 

P (J and NR) = 0.4 * 0.4 = 0.16 [Probability John practicing and it is not raining] 

Hence; 

Probability of John practicing regardless of weather condition is 

P(John Practicing) = 0.48 + 0.16 = 0.64

HOPE THIS HELPED!!!

7 0
3 years ago
Solve the system of equations by graphing<br> y =<br> .5x – 3<br> {<br> y= {x - 3
Sergeu [11.5K]

Answer:

I don't think I know it sorry

3 0
3 years ago
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Ratling [72]
81.7%

This is because the area of the inside circle is roughly 18.3% of the big circle. You can get this by finding both of their areas and then dividing the inside circle by the outside one. 
8 0
2 years ago
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