9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
34! Find the area of each of the six sides and then add them up:)
You first do 3 + 2, which would equal 5. Then, you would just do 3/5.
Answer:
20.428571
Step-by-step explanation:
C=(22/7)d
C=(22/7)6.5
C=20.428571
