Ask question

Ask question

All categories

3 years ago

15

Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (0, 0), r = 4

1 answer:

Ad libitum [116K]3 years ago

8 0

Answer:

$x^2+y^2=16$

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by the formula;

$(x-h)^2+(y-k)^2=r^2$

Given (h,k)=(0,0) and r=4, we substitute the values to obtain;

$(x-0)^2+(y-0)^2=4^2$

The required equation is

$x^2+y^2=16$

You might be interested in

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.

Korolek [52]

Chloe and Fiane will each have 9 flash cards in 1 minute.

3 0

3 years ago

Read 2 more answers

Factor completely 3X^2 -25

Dominik [7]

In order to factor a polynomial, you have to find its roots

$x_1,\ x_2,\ldots,x_n$

So that you can factor it as

$p(x)=(x-x_1)(x-x_2)\cdots(x-x_n)$

So, in this case, we're looking for the solutions of

$3x^2-25=0 \iff 3x^2=25 \iff x^2 = \dfrac{25}{3} \iff x=\pm\sqrt{\dfrac{25}{3}}=\pm\dfrac{5}{\sqrt{3}}$

So, the polynomial can be written as

$3x^2-25 = \left(x-\dfrac{5}{\sqrt{3}}\right)\left(x+\dfrac{5}{\sqrt{3}}\right)$

5 0

3 years ago

M∠GFZ = 38°, m∠ZFE = 2x+ 125, and m∠GFE = x+ 163. Find x.

igomit [66]

Answer:

equation : 38 + 2x + 125 = x + 163

x : 0

if GFE is the entire thing, and GFZ and ZFE are adjacent angle(connected by a line), then GFZ + ZFE = GFE

hope this helps :)

7 0

3 years ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2y x {}^{ - 4} }{2x {}^{ - 13} y {}^{ - 9} }$

$= x {}^{9} y {}^{ - 8}$

$= \frac{x {}^{9} }{y {}^{8} }$

12.

$( \frac{2u {}^{ 4} }{ - u {}^{2}v {}^{ - 1} \times 2uv {}^{ - 4} } ) {}^{ - 1}$

$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

$= - u {}^{ - 1} v {}^{ - 5} = - \frac{ 1}{uv {}^{5} }$

13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4}n {}^{ - 1} }{ - m {}^{ - 2} n {}^{2} \times - nm {}^{ - 3} }$

$- \frac{2m {}^{4} n {}^{ - 1} }{m {}^{ - 5}n {}^{3} } = - 2m {}^{9} n {}^{ - 4}$

$= - \frac{2m {}^{9} }{n {}^{4} }$

14.

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{2} y {}^{ - 3} \times yx {}^{0} } ) {}^{3}$

$( \frac{x {}^{3}y {}^{ - 4} }{ - {x}^{ - 2}y {}^{ - 2} } ) {}^{3}$

$( - {x}^{5} y {}^{ - 2} ) {}^{3} = - x {}^{15} y {}^{ - 6}$

$- \frac{x {}^{15} }{ {y}^{6} }$

15.

$- \frac{yx {}^{4} \times - {y}^{3} z { }^{ - 4} }{(z {y}^{2} ) {}^{4} }$

$- \frac{ - y {}^{4} x {}^{4} z {}^{ - 4} }{ {z}^{4} y {}^{8} } = - y {}^{4} x {}^{4} z {}^{ - 8} = - \frac{(xy) {}^{4} }{ {z}^{8} }$

16.

$\frac{h {}^{7}j {k}^{4} }{4h {}^{4} } = \frac{1}{4} h {}^{3} = \frac{h {}^{3} jk {}^{4} }{4}$

6 0

2 years ago

1. Write the fraction as a decimal.<br> (1 Point)<br> 1<br> 10

Iteru [2.4K]

Answer:

he fraction 1/10 would be written as the decimal 0.1.

Step-by-step explanation:

8 0

3 years ago