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3 years ago

15

Find the equation of the circle in standard form for the given center (h, k) and radius r: (h, k) = (0, 0), r = 4

1 answer:

Ad libitum [116K]3 years ago

8 0

Answer:

$x^2+y^2=16$

Step-by-step explanation:

The equation of a circle with center (h,k) and radius r is given by the formula;

$(x-h)^2+(y-k)^2=r^2$

Given (h,k)=(0,0) and r=4, we substitute the values to obtain;

$(x-0)^2+(y-0)^2=4^2$

The required equation is

$x^2+y^2=16$

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Factor completely 3X^2 -25

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3 years ago

M∠GFZ = 38°, m∠ZFE = 2x+ 125, and m∠GFE = x+ 163. Find x.

igomit [66]

Answer:

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x : 0

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3 years ago

Anyone, please help me please answer my question because I have to pass this tomorrow morning:(

Wittaler [7]

Step-by-step explanation:

If you need help with how I got my answer, you can ask me.

$\frac{2yx {}^{ - 4} }{(x {}^{ - 4}y {}^{4}) {}^{3} \times 2x {}^{ - 1}y {}^{ - 3} }$

$\frac{2yx {}^{ - 4} }{x {}^{ - 12}y {}^{12} \times 2x {}^{ - 1}y {}^{ - 3} }$

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$( \frac{2u {}^{4} \times 1 }{ - 2 {u}^{3}v {}^{ - 5} } ) {}^{ - 1}$

$( - u v {}^{ 5} ) {}^{ - 1}$

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13.

$- \frac{2m {}^{4}n {}^{ - 1} }{( - m {}^{2}n {}^{ - 2}) {}^{ - 1} \times - nm {}^{ - 3} }$

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2 years ago

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Iteru [2.4K]

Answer:

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Step-by-step explanation:

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