So there where two times the amount of rock tickets sold than the jazz concert. If that is it then you divide the 1840 by 2 getting 920, dividing 1÷2 you get zero remainder 1, 18÷2= 9, 4÷2= 2, and 0÷2= 0. 920. Hope i helped :)
Answer:
240
Step-by-step explanation:
Gain=25%
Gain=selling price - cost price
Gain = ((selling price - cost price )× 100)/ cost price
25c=(4800-c)100
25c=480000-100c
125c=480000
cost price = 3840
second statement
The selling price was 4080
Cost price 3840
therefore
Gain=selling price - cost price
Gain = 4080-3840
=240
We want to create a linear equation to model the given situation.
A) c(r) = $6.00 + $1.50*r
B) 19 rides.
We know that the carnival charges $6.00 for entry plus $1.50 for each ride.
A) With the given information we can see that if you ride for r rides, then the cost equation will be:
c(r) = $6.00 + $1.50*r
Where c(r) is the cost for going to the carnival and doing r rides.
B) If you have $35.00, then we can solve:
c(r) = $35.00 = $6.00 + $1.50*r
Now we can solve the equation for r.
$35.00 = $6.00 + $1.50*r
$35.00 - $6.00 = $1.50*r
$29.00 = $1.50*r
$29.00/$1.50 = r = 19.33
Rounding to the next whole number we get: r = 19
This means that with $35.00, Dennis could go to 19 rides.
If you want to learn more, you can read:
brainly.com/question/13738061
Answer:
No, a triangle cannot be constructed with sides of 2 in., 3 in., and 6 in.
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
2
in.
+
3
in.
=
5
in.
5
in.
<
6
in.
For a triangle with sides 3 in., 4 in. and 5 in. which can form a triangle:
3 + 4 = 7 which is greater than 5
3 + 5 = 8 which is greater than 4
4 + 5 = 9 which is greater than 3
Step-by-step explanation:
Answer:
The values of 
and 
are 
and 
, respectively.
Step-by-step explanation:
The statement is equivalent to the following mathematic expression:
(1)
By definition of the perfect square trinomial:
And by direct comparison we have the following system:
(2)
(3)
By (3), we solve for :
The values of and are and , respectively.
