What is the slope intercept ?<br><br> Please help me !!!

Determine whether the distribution below represents a probability distribution.

baherus [9]

Answer:

No, not a probability distribution.

Step-by-step explanation:

It appears that one of the probabilities in the table (-.3) is negative, which is not allowed.

8 0

2 years ago

Hello, I am stuck on how to solve the matrix problem of x - y = 5

Sergio [31]

If you’re trying to elimination the answer would be (14,9)

4 0

3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$

a) Determine the 26th percentile for the number of chocolate chips in a bag. 

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

$Z = \frac{X - \mu}{\sigma}$

$-0.643 = \frac{X - 1262}{118}$

$X - 1262 = -0.643*118$

$X = 1186$

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{X - 1262}{118}$

$X - 1262 = -1.96*118$

$X = 1031$

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

$Z = \frac{X - \mu}{\sigma}$

$1.96 = \frac{X - 1262}{118}$

$X - 1262 = 1.96*118$

$X = 1493$

Between 1031 and 1493.

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 1262}{118}$

$X - 1262 = -0.675*118$

$X = 1182$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 1262}{118}$

$X - 1262 = 0.675*118$

$X = 1342$

IQR:

1342 - 1182 = 160

7 0

3 years ago

jessica has a jewelry box with a base of 18 square inches. the height is 7 inches. what is the volume of her jewelry box?

ozzi

Assuming it is a right rectangular prism, the volume is 126 sq. in.

V = area of base * height = 18 * 7 = 126

6 0

3 years ago

Read 2 more answers

Julia used 1 foot square stone tiles to make a patio. She laid the tiles in a square, 7 tiles wide by 7 tiles long. What is the

marshall27 [118]

Answer: $49\ ft^2$

Step-by-step explanation:

The formula that is used to calculate the area of a square is this one:

$A=s^2$

Where "s" is the side lenght of the square

You know that Julia used 1 foot square stone tiles, then each side lenght of the this tiles is:

$s_{tile}=\sqrt{1\ ft^2}\\\\s_{tile}=1\ ft$

Since Julia laid 7 tiles wide by 7 tiles long, the side lenght of the new patio is:

$s_{patio}=7(1\ ft)\\\\s_{patio}=7\ ft$

Therefore its area is:

$A_{patio}=(7\ ft)^2\\\\A_{patio}=49\ ft^2$

5 0

3 years ago

Read 2 more answers

What is the slope intercept ? Please help me !!!