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Iteru [2.4K]
3 years ago
11

Marge cut 16 pieces of tape for mounting pictures on posterboard each piece of tape is 3/8 inches long how much tape did Marge u

se
Mathematics
1 answer:
daser333 [38]3 years ago
7 0

Answer:

6 inches of tape

Step-by-step explanation:

To find the total amount of tape that Marge used, you can take the measure of each piece (\frac{3}{8}) and multiply by the total number of pieces cut (16):

\frac{3}{8}*\frac{16}{1}=\frac{48}{8}=6inches

So, Marge used 6 inches of tape altogether.

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Does 23^-1 (mod 1000) exist? If yes solve it.
sweet [91]

Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).

Let <em>x</em> be the inverse. Then <em>x</em> is such that

23<em>x</em> ≡ 1 (mod 1000)

Use the Euclidean algorithm to solve for <em>x</em> :

1000 = 43×23 + 11

23 = 2×11 + 1

→   1 ≡ 23 - 2×11   (mod 1000)

→   1 ≡ 23 - 2×(1000 - 43×23)   (mod 1000)

→   1 ≡ 23 - 2×1000 + 86×23   (mod 1000)

→   1 ≡ 87×23 - 2×1000 ≡ 87×23   (mod 1000)

→   23⁻¹ ≡ 87   (mod 1000)

3 0
3 years ago
What expression is equivalent to 6+3(n-4)-8+2n
lorasvet [3.4K]

Answer:

Step-by-step explanation:

Comment

Begin by removing the brackets.

6+3(n-4)-8+2n

6 + 3n - 12 - 8 + 2n                 Collect like terms

3n + 2n + 6 - 12 - 8                 Combine

5n - 14

Answer

5n - 14

4 0
2 years ago
Can anyone help me with this math problem? Thank you.
pickupchik [31]

Step-by-step explanation:

Answer is in the picture.

4 0
3 years ago
Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 m
MrRissso [65]

Answer:

The faster train goes 60mph

Step-by-step explanation:

s= speed

s+20 is the faster train.

Then you are given:

200/s+s+20=2

200=2*(2s+20)

4s+40=200

4s=160

s=40 is the slower train

40+20= speed of faster one

s=60 ;)

6 0
3 years ago
Jaden is flying a kite with an angle of elevation of 33 degrees. If Jaden lets out 275 feet of string, how high above the ground
pshichka [43]

Answer:

149.8 feet

Step-by-step explanation:

θ = Angle of elevation = 33°

The length of string Jaden lets out = Hypotenuse = 275 feet.

How high above the ground that the kite is flying = Opposite Side.

We are solving this question using the Trigonometric function of Sine

Sin θ = Opposite Side/Hypotenuse

Sin 33 = Opposite/275 feet

Cross Multiply

Sin 33 × 275 feet = Opposite

Opposite side(Height ) = 149.77573463 feet

Approximately to the nearest tenth = 149.8 feet

8 0
2 years ago
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