Yes, 23 has an inverse mod 1000 because gcd(23, 1000) = 1 (i.e. they are coprime).
Let <em>x</em> be the inverse. Then <em>x</em> is such that
23<em>x</em> ≡ 1 (mod 1000)
Use the Euclidean algorithm to solve for <em>x</em> :
1000 = 43×23 + 11
23 = 2×11 + 1
→ 1 ≡ 23 - 2×11 (mod 1000)
→ 1 ≡ 23 - 2×(1000 - 43×23) (mod 1000)
→ 1 ≡ 23 - 2×1000 + 86×23 (mod 1000)
→ 1 ≡ 87×23 - 2×1000 ≡ 87×23 (mod 1000)
→ 23⁻¹ ≡ 87 (mod 1000)
Answer:
Step-by-step explanation:
Comment
Begin by removing the brackets.
6+3(n-4)-8+2n
6 + 3n - 12 - 8 + 2n Collect like terms
3n + 2n + 6 - 12 - 8 Combine
5n - 14
Answer
5n - 14
Step-by-step explanation:
Answer is in the picture.
Answer:
The faster train goes 60mph
Step-by-step explanation:
s= speed
s+20 is the faster train.
Then you are given:
200/s+s+20=2
200=2*(2s+20)
4s+40=200
4s=160
s=40 is the slower train
40+20= speed of faster one
s=60 ;)
Answer:
149.8 feet
Step-by-step explanation:
θ = Angle of elevation = 33°
The length of string Jaden lets out = Hypotenuse = 275 feet.
How high above the ground that the kite is flying = Opposite Side.
We are solving this question using the Trigonometric function of Sine
Sin θ = Opposite Side/Hypotenuse
Sin 33 = Opposite/275 feet
Cross Multiply
Sin 33 × 275 feet = Opposite
Opposite side(Height ) = 149.77573463 feet
Approximately to the nearest tenth = 149.8 feet
