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2 years ago

10

Find 5 rational numbers between 6/8 and 7/2

2 answers:

stepan [7]2 years ago

6 0

Answer:

uh cuzxbjcxlkz

Step-by-step explanation:

In a plain, robust, conversational style, the author known as “Elena Ferrante” has captivated readers worldwide with her chronicle of a complicated friendship between two women.

Tamiku [17]2 years ago

3 0

Step-by-step explanation:

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

So simply name any fractions between 6/8 and 7/2 will do

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Simplify the expression 4 (9x)

Naddika [18.5K]

Answer:

36x

Multiply x and 9

Multiply x and 1

The x just gets copied along.

The answer is x

x

9*x evaluates to 9x

Multiply 4 and 9x

Multiply 1 and x

The x just gets copied along.

x

4*(9*x) evaluates to 36x

The final answer is

36x

8 0

3 years ago

Read 2 more answers

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kari74 [83]

The answer would be $19 on eg

4 0

3 years ago

Hello answer and I will give you brainliest:No cheating!

stich3 [128]

The answer is 58,875

6 0

2 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

charle [14.2K]

ANSWER

See below

EXPLANATION

Given

$f(x) = \frac{ {x}- 9 }{x + 5}$

and

$g(x) = \frac{ - 5x - 9}{x - 1}$

$(f \circ \: g)(x)= \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }$

Expand:

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9 - 9x + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 5x - 9x + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }$

$(f \circ \: g)(x)= \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }$

Since the denominators are the same, they will cancel out,

$(f \circ \: g)(x)= \frac{ - 14x}{ - 14} = x$

8 0

2 years ago

Whats the answer PLS

Alexxx [7]

Answer:

48+23(6)½

Step-by-step explanation:

A = l × w

A =[(8-(6)^½) × (9+4(6)^½)]

A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]

A =(72 + 32(6)^½ - 9(6)^½ - 24)

A =(72 - 24 + 32(6)^½ - 9(6)^½)

A =(48 + 23(6)^½)

3 0

3 years ago