Answer:
Another point is (3,1) and the vertex is (0,0)
Step-by-step explanation:
The vertex is still (0,0) since the parabola has only been stretched some way and not shifted from the parent function f(x)=x^2.
Enter in any x you like like 3 (I chose 3 because I see I'm going to multiply by 1/3). Anyways
g(3)=(1/3*3)^2=(1)^2=1 so another point on the parabola is (3,1)... Now just use the fact that all parabolas are symmetrical to graph it.
