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3 years ago

What type of function is represented in the table?

Mathematics

1 answer:

nadezda [96]3 years ago

3 0

Answer:

Step-by-step explanation:

quadratfunction because it comprises of both X and Y

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Help me with this question I will mark brainlist no web link Solve :- 9n²-64=0

Archy [21]

Factorize

(3n + 8) (3n - 8) = 0
3n + 8 = 0 and 3n - 8 = 0

Solve both for n

3n + 8 = 0
3n = -8
n = -8/3

3n - 8 = 0
3n = 8
n = 8/3

Therefore n = -8/3 and n = 8/3

6 0

3 years ago

Gwen says that the sum of -1 3/4 and 2 1/2 is the same as the difference between 2 1/2 and 1 3/4. Is Gwen correct? Explain why o

solong [7]

Answer: No

Step-by-step explanation: no because one is negative 1 3/4 and the other one isint in the negatives

4 0

3 years ago

Factor the polynomial 8x² − 24x − 224 completely

NeTakaya

Answer:

8(x+4)x(x-7)

Step-by-step explanation:

hope this helps!

3 0

3 years ago

What is 0.01 rounded to the nearest hundredth

Novosadov [1.4K]

Answer:

It is already rounded to the nearest tenth! Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

3 years ago