All categories

3 years ago

Can someone explain how you got the answer!!

Mathematics

1 answer:

gavmur [86]3 years ago

6 0

9514 1404 393

Answer:

20 square units

Step-by-step explanation:

The area is given by the formula ...

A = bh

where b is the base of the parallelogram, and h is the perpendicular distance between the parallel bases. Using the numbers from the figure, we have ...

A = 5·4 = 20 . . . . square units

_____

<em>Additional comment</em>

You will notice this is the same formula as is used for a rectangle. You can consider the parallelogram to have the same area as a rectangle of these dimensions if you look at what happens when you cut the right triangle from the right end and add it to the left end. The result is a rectangle 5 units wide and 4 units high.

The same formula applies even if the skew is so great that the bases do not overlap. (That much skew would not result in a triangle of the kind shown in this diagram.)

You might be interested in

Name the property of equality that justifies the statement if a equals b then b equals a

SpyIntel [72]

That would be the commutative property

3 0

3 years ago

The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented

leva [86]

The equation of the hyperbola is : $\frac{x^{2}}{48^2} - \frac{y^{2}}{14^2} = 1$

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

$d= \frac{a^{2}}{c}$

Here the directrix line is given as : x= 2304/50

Thus, $\frac{a^{2}}{c} = \frac{2304}{50}$

⇒ $\frac{a^{2}}{50} = \frac{2304}{50}$

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : $\frac{x^{2}}{48^2} - \frac{y^{2}}{14^2} = 1$

5 0

3 years ago

Read 2 more answers

Simplify to the lowest terms

Black_prince [1.1K]

Answer:

1/2

Step-by-step explanation:

divide the numerator & denominator by 4

4 0

3 years ago

25 POINTS AND BRAINLIEST PLEASE HELP ASAP

dexar [7]

M is a midpoint of BC so:

$M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)$

Length of MA:

$MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=
\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

Length of NB:

$NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\
\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}$

5 0

3 years ago

Read 2 more answers

Which rule yields the dilation of the figure JKLM centered at the origin?

Sphinxa [80]

I’d say it’s between B and D

3 0

3 years ago

Read 2 more answers