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horrorfan [7]
3 years ago
14

The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). At which points could the vertex of the right angle in t

he triangle be located? The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).
At which points could the vertex of the right angle in the triangle be located? Check all that apply.
(–1, 1)
(4, –2)
(1, 1)
(2, –2)
(4, –1)
(–1, 4)
Mathematics
2 answers:
bixtya [17]3 years ago
4 0

Answer:

(-1,1),(4,-2)

Step-by-step explanation:

Pie3 years ago
3 0

Answer:

(–1, 1)  and (4, –2)

Step-by-step explanation:

we know that

The vertex of the right angle of the triangle could be situated at a point with the same x-coordinate of point A and the same y-coordinate of point B or at a point with the same x-coordinate of point B and the same y-coordinate of point A

we have

A(4, 1) and B(–1, –2)

so

a point with the same x-coordinate of point A and the same y-coordinate of point B is the point (4,-2)

a point with the same x-coordinate of point B and the same y-coordinate of point A is  (-1,1)

therefore

(–1, 1)  and (4, –2)

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Troyanec [42]

Answer:

Option C

Step-by-step explanation:

we have

-6x^{2} -6x+12=0

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-6x^{2} -6x=-12

step 2

Factor -6 leading coefficient'

-6(x^{2} +x)=-12

step 3

Complete the square

Remember to balance the equation by adding the same constants to each side

-6(x^{2} +x+0.25)=-12-1.5

-6(x^{2} +x+0.25)=-13.5

step 4

Rewrite as perfect squares

-6(x+0.5)^{2}=-13.5

simplify

(x+0.5)^{2}=2.25

5 0
4 years ago
Read 2 more answers
The diameter of a circle is 6 m. Find its area in terms of π π.
Xelga [282]

Step-by-step explanation:

this is totally simple.

the formula for the area of a circle (as you can find with any search on the internet in seconds) :

A = pi×r²

r is the radius.

and once you understand even the most basics of a circle, you know that the radius is half of the diameter.

so, in our case, r = 6/2 = 3 m

the area of the circle is therefore

pi×r² = pi×3² = pi×9 m²

4 0
3 years ago
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Y=1/3x-3<br> Y=-x+5 <br> How do I solve
ehidna [41]

Since both equations are equal to y, we can just combine them like this:

1/3x-3=-x+5

1/3x=-x+8

4/3x=8 (since x is 1x which is 3/3x)

x=6

Plug x back in:

y=-6+5

y=-1

So x=6 and y=-1

Hope this helped!

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4 years ago
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jek_recluse [69]

Step-by-step explanation:

this sequence is geometric not arithmetic

HOw we know that ??

when we get a common difference  that must Be equal  

d=6-2=4  not equal to  d=18-6=12

So it is not arithmetic

but when we get the common ratio that also must be equal

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So it is geometric

By using this equation:

a(n)=a(1)*r^(n-1)

and we have a(1)=2 , r=3    

<u>Explicit rule:</u> a(n)=2*(3)^(n-1)

<u>Recursive rule:</u>  a(n)= r * a(n-1)

a(n-1) ⇒ priviuse term

SO:  a(n)= 3 * a(n-1)

For example:

a(3)= 3 * 6 =18

<em>I really hope this helps <3</em>

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Answer:

sorry bro don't read Spanish but it's not over 3

Step-by-step explanation:

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