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irinina [24]
3 years ago
9

A cyclist rides her bike at a rate of 8 miles per hour. What is this rate in kilometers per hour? How many kilometers will the c

yclist travel in 4 hours? In your computations, assume that 1 mile is equal to 1.6 kilometers. Do not round your answers.
Mathematics
2 answers:
alina1380 [7]3 years ago
6 0
1 mile is equal to 1.6 kilometers, so 8 miles (using a direct proportion) should be equal to 8 * 1.6 = 12.8 kilometers. The cyclist rides at 12.8 kilometers per hour. In four hours, the cyclist would have rode 12.8 * 4 = 48 + 3.2 = 51.2 kilometers.
musickatia [10]3 years ago
4 0

Answer:

51.2

Step-by-step explanation:

just took the test

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nata0808 [166]

Answer:

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6 0
3 years ago
A bag has 1 orange lollipop
Marysya12 [62]

Answer: The probability of getting a white is POSSIBLE and the probability of not getting a white is black

Step-by-step explanation:

4 0
3 years ago
3. Find cos(A). Show your work and reduce the ratio if necessary.
anygoal [31]

Answer:

cosA = \frac{3}{5}

Step-by-step explanation:

cosA = \frac{adjacent}{hypotenuse} = \frac{AB}{AC} = \frac{30}{50} = \frac{3}{5}

5 0
3 years ago
A glass is 1/3 full.
Setler79 [48]

Answer:

216 cm³

Step-by-step explanation:

1/3x + 63 = 5/8x

subtract 1/3x from each side; (1/3x = 8/24x  and  5/8x = 15/24x)

63 = 7/24x

7x = 63(24)

7x = 1512

x = 216

4 0
3 years ago
An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s
UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= \frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }

a) 95% CI

(X[bar]_1 - X[bar]_2) ± t_{n_1 + n_2 - 2}*Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }

Sa²= \frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}= \frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}= 0.5

Sa= 0.707ç

t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306

(4.7-6.9) ± 2.306* (0.707\sqrt{\frac{1}{5}+\frac{1}{5} })

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

b.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0
3 years ago
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