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rodikova [14]
3 years ago
11

If you are trying to compare 2 loans, one that pays 3.15% compounded mounthly for 4 years and another that pays 2.95% compounded

weekly for 4.5 years, what is the APY of the cheaper loan?
Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0
.......................
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What is the range of 220,2100,260,5160.​
IrinaVladis [17]

Answer:

range is the biggest number minus the smallest number

Step-by-step explanation:

so 5160-220=4940

7 0
3 years ago
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Resultant Terms in Exponential Form 13^-11 * 13^16 * 13^-3 * 13^4 * 13^-5
Yuki888 [10]
Easy
remember
(x^m)(x^n)=x^(m+n)
basically add exponens when the base is same
(13^-11)(13^16)(13^-3)(13^4)(13^-5)=
13^(-11+16-3+4-5)=
13^(5-4)=
13^1=13
6 0
3 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
Andrew is showing his work in simplifying (−5.7 + 2.2) − 1.1.
Leviafan [203]
Answer: In step 1, Andrew used the commutative property

Explanation:
In step 1 he used commutative, which is a + b = b + a
(- 5.7 + 2.2) = 2.2 + (- 5.7)

Step 2, he used associative property, not the distributive.

Step 3, he just added5.7 + 1.1 = 6.8

Step 4, he distributed the negative sign:
- (6.8) = - 6.8
6 0
2 years ago
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If sin= 7/25 what are the other primary trig ratios?
statuscvo [17]

Answer:

cos=24/25

tan=7/24

Step-by-step explanation:

sin=opposite/hypotenuse

therefore 7 is the opposite and 25 is the hypotenuse.

using pythagorean theorem we can find the adjacent. i.e hypotenuse squared= sum of adjacent squared and opposite squared.

h^2= a^2+ O^2

25 squared - 7 squared= 576

which is equal to 24 squared.

therefore adjacent=24

cos=adjacent/hypotenuse

cos=24/25

tan=opposite/adjacent

tan=7/24.

8 0
2 years ago
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