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Darina [25.2K]
2 years ago
8

Please help asap. will mark brainliest

Mathematics
1 answer:
Dmitriy789 [7]2 years ago
6 0

Answer:

he has 300 nickels

Step-by-step explanation:

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3 years ago
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What two numbers multiply to 11 and add to -16
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They're irrational numbers, so they can't be exactly written down.
Rounded to the nearest thousandth, they are

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3 years ago
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Baxter has a sandbox that holds Kinetic sand. The diagram
NARA [144]

It's a cuboid

  • Length=L=3-3/4=3.75ft
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A k out of n system is one in which there is a group of n components, and the system will function if at least k of the componen
Solnce55 [7]

Answer:

0.9606 = 96.06% probability that the system will function tomorrow

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works, or it does not. Components are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of a component working:

0.7 of 0.2(rain)

0.9 of 1 - 0.2 = 0.8(no rain). So

p = 0.7*0.2 + 0.9*0.8 = 0.86

0.86 - 86% probability that the system will function tomorrow

6 components:

This means that n = 6

What is the probability that the system will function tomorrow

This is

P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{6,4}.(0.86)^{4}.(0.14)^{2} = 0.1608

P(X = 5) = C_{6,5}.(0.86)^{5}.(0.14)^{1} = 0.3952

P(X = 6) = C_{6,6}.(0.86)^{6}.(0.14)^{0} = 0.4046

P(X \geq 4) = P(X = 4) + P(X = 5) + P(X = 6) = 0.1608 + 0.3952 + 0.4046 = 0.9606

0.9606 = 96.06% probability that the system will function tomorrow

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2 years ago
Help please odds only geometry
nikklg [1K]
1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h  +  j ;

2) 
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;

3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j  -  h ;

4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
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3 years ago
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