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Lelechka [254]
3 years ago
7

Round 8.61 to the nearest tenth.

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0
8.61 to the nearest tenth is 8.6 because the 1 tells you the 6 will not change.
maks197457 [2]3 years ago
5 0
8.6 first number after the decimal is the tenths place then the second number after the decimal is the hundredths
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B5%7D%20%20-%207%20%3D%204" id="TexFormula1" title=" \frac{x}{5} - 7 = 4"
Anestetic [448]
Hello! And thank you for your question!

First add 7 to both sides:

x/5 = 4 + 7

Then simplify 4 + 7:

x/5 = 11

After that, multiply both sides by 5

11 x 5 = x

Finally, Simplify 11 * 5:

x = 55

Final Answer:

x = 55
3 0
4 years ago
Find the reciprocal of the number. Multiply to check your answer.
iren [92.7K]
To find the reciprocal, you just flip the fraction upside down, so it would be D
4 0
3 years ago
Read 2 more answers
Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²
IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

a^2-b^2=(a-b)(a+b)

Let us examine each of the given equation

\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}

From the above,

\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

3 0
1 year ago
How do you find the answer to this?
Stels [109]

Answer:

  D)  {-1}

Step-by-step explanation:

A rational expression is "not defined" when its denominator is zero. Hence to find values of x that make the expression "not defined," you solve the equation ...

  denominator = 0

  2x +2 = 0 . . . . . . put the actual denominator into the equation

  x + 1 = 0 . . . . . divide by 2

  x = -1 . . . . . . . . subtract 1

The expression is "not defined" for x in the set {-1}.

3 0
3 years ago
What postulate or theorem proves the two triangles are similar?
11111nata11111 [884]

Answer:

sss therom

Step-by-step explanation:

they are congruent on all sides

8 0
3 years ago
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