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Fiesta28 [93]
2 years ago
11

What are the zero of the functions?

Mathematics
1 answer:
EleoNora [17]2 years ago
8 0

Answer:

x= -4 x=-2

Step-by-step explanation:

factor the function and get

(x+4)(x+2)=0

therefore

x=-4 or x=-2

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Write the equation of the line through each point.
Leya [2.2K]

Answer:

The equation would be y = -1/3x + 4

Step-by-step explanation:

The first step to finding this equation needs to be solving the first equation for y so that we can find the slope.

-3x + y = 1

y = 3x + 1

Now that we have the slope of 3, we know the slope of a perpendicular line would be -1/3. This is because perpendicular lines have opposite and reciprocal slopes. We can then use this and the point to solve in point-slope form.

y - y1 = m(x - x1)

y - 2 = -1/3(x - 6)

y - 2 = -1/3x + 2

y = -1/3x + 4

5 0
3 years ago
I need help with point slope formula bad
NISA [10]
Ok so this question:
y + 1 = - ( x - 2 )        (distribute the negative inside the parenthesis)
y + 1 = -x + 2             (substitute the y= -1)
-1 + 1 = -x + 2
0 = -x + 2                   (take two to the other side)
-2 = -x                        (divide the negative away from x)
2 = x

3 0
2 years ago
Graph the system of equations. {x−y=64x+y=4
Fantom [35]
X-y=6 Equation 1
x+y=4 Equation 2

To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
x=6  Point is (6,0)
When x=0
-y=6
y=-6  Point is (0,-6)

Now x-intercept and y-intercept for equation 2.
x+y=4
When x=0
y=4  Point is (0,4)
When y=0
x=4 Point is (4,0)

Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.

Answer: (5,-1)

5 0
3 years ago
Find the lowest common multiple (LCM) of 15 and 30.<br><br>A) 5<br>B) 15<br>C)30<br>D)60​
12345 [234]

Answer:

L.C.M of 15 and 30 is 30.

7 0
3 years ago
Math<br> math<br> math<br> math<br> math
ki77a [65]

Answer:

D

Step-by-step explanation:

Add 7 and 3 which is 10

3^10 is 59049 which is the same as 3^7*3*3

7 0
2 years ago
Read 2 more answers
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