Hundredths are the second number after the decimal, which is the 7. The number, 5.476, rounded is 5.48. You round numbers by looking at the number after what place you want to round by. For example, if I had 5.28 and wanted to round it to the nearest tenths, I would look at the number after 2, which is 8. If the number is 5 or higher and one to the place you need to the round. If it’s 4 or lower, just take away the numbers after the place you need to round, so it would be 5.3. However, if it was 5.23 and I wanted to round it to the tenths, I would just take away the three, making it 5.2
Answer:
16x-20
Step-by-step explanation:
(8x-30)+6x+(2x+10)
8x-30+6x+2x+10
8x+6x+2x-30+10
14x+2x-20
16x-20
y ≤ x − 5
y ≥ −x − 4
This is a check and see type of problem.
if x=5
y ≤ 5 − 5 y≤ 0
y ≥ −5 − 4
y ≥-9
-9≤ y ≤ 0
-2 works so (5,-2) is a solution
if x= -5
y ≤ -5 − 5 y≤ -10
y ≥ 5 − 4
y ≥1
no solution
Choice B (5,-2)
The dimensions of the house should be 7 m by 13 m.
If the house is to be centered, we will take the same amount from the width as we do from the length of the lot for the dimensions. This gives us (10-x) and (16-x) as the dimensions.
The area of a rectangle is found by multiplying the length and width:
(10-x)(16-x) = 91
Multiplying the binomials we have:
10*16 - x*10 - x*16 -x*(-x) = 91
160 - 10x - 16x --x² = 91
160-10x-16x+x² =91
Combine like terms:
160-26x+x²=91
Rewrite this in standard form:
x²-26x+160=91
Subtract 91 from both sides:
x²-26x+160-91 = 91-91
x²-26x+69 = 0
Factoring this, we look for factors of 69 that sum to -26. -23*-3 = 69 and -23+-3 = -26, so:
(x-23)(x-3) = 0
Using the zero product property we know that either x-23=0 or x-3=0, so x=23 or x=3.
x was the amount we take off of the width and length of the lot; if we took 23m off of it, 10-23 gives us a negative amount, which is not realistic. This means both the width and length are subtracted by 3.
10-3 = 7 and 16-3 = 13.
These are the dimensions of the house.
The answer is 80 because the answer for all three sides should be 180
