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4 years ago

In a dilation with a scale factor of 3/4,the image is __________ the preimage

1 answer:

3 0

I would say smaller than because you would be dilating the image by a number less than 1, which is making the image smaller.

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Write an equation of the line that passes through the point (3,0) and<br> has the slope, m = -2.

kenny6666 [7]

The equation of a line is Y=mx+b
You know that the slope is -2 and the slope is 'm' so sub it into the equation.
Y=-2x+b
To have an equation of a line you need the 'b' or 'y' intercept and the slope.
This means you have to find the 'b' because you already know the slope which is -2. To find the 'b' you have to sub in the coordinates and then solve for 'b'
Y=-2x+b
(x,y)
(3,0)
0=-2(3)+b
0=-6+b
6=b
Therefore the equation of the line is Y=-2x+6 <span />

6 0

4 years ago

If cos theta = 0.3090, which of the following represents approximate values of sin thetha for 0 degrees <90 degrees? A. sin t

artcher [175]

In this question, the given value is

$cos \theta = 0.3090$

And we have to find the value of sin theta and tan theta where theta is in first quadrant .

And in first quadrant, all are positive .

Now we use the formula, which is

$sin \theta = \sqrt{1-cos^2 \theta} = \sqrt{1 - 0.3090^2} = 0.9511$

And tan theta is the ratio of sin theta and cos theta, that is

$tan \theta = \frac{sin \theta}{ cos \theta} = \frac{0.9511}{0.3090} =3.078$

So the correct option is B .

4 0

3 years ago

Read 2 more answers

Y/x^2 + y/x^3<br><br>perform the operation and express your answer as a single fraction

umka2103 [35]

Answer:

$\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}$

Step-by-step explanation:

Given the expression

$\frac{y}{x^2}+\frac{y}{x^3}$

Let us perform the operation and express your answer as a single fraction

$\frac{y}{x^2}+\frac{y}{x^3}=\frac{x^3y+x^2y}{x^5}$

$=\:\frac{x^2\left(xy+y\right)}{x^5}$

$=\frac{\left(xy+y\right)}{x^3}$

Therefore, we conclude that:

$\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}$

3 0

3 years ago

Determine whether y2=3x+1 is a function.

bazaltina [42]

Answer: it is not a function

Step-by-step explanation:

Given :

$y^{2}$ = 3x + 1

The first thing is to make y the subject of the formula, that means we will take the square root of both sides

y = $\sqrt{3x + 1}$

since y = $\sqrt{3x + 1}$ , the the value of y could be positive or negative.

For example , $\sqrt{4}$ = ± 2 , since -2 x -2 will also give + 4

For y = $\sqrt{3x + 1}$ to be a function , there must be a unique value for y for each value of x , but this is not the case as y could be positive or negative for a single value of x , so it is not a function.

4 0

3 years ago

Heather spent $138 on shirts. Fancy shirts cost $26 and plain shirts cost $15. If she bought a total of 7, then how many of each

Jlenok [28]

She bought about 3.5

3 0

4 years ago