Ask question

Ask question

All categories

4 years ago

14

A cheetah runs at a speed of 56 miles for every hour. If the distance traveled, in miles, is d and time, in hours, is t, which e

quation shows the relationship between d and t? t = 56d
d = 56t
d = 56 + t
t = 56 + d

1 answer:

Butoxors [25]4 years ago

6 0

D=56t because if t is hrs then u would multiply 56 and t to find the miles per hour

You might be interested in

How to tell whether lines are parallel perpendicular or neither?

julsineya [31]

The way they are turned

6 0

3 years ago

The computer center at Dong-A University has been experiencing computer down time. Let us assume that the trials of an associate

Schach [20]

Answer:

(a)0.16

(b)0.588

(c) $[s_1$ s_2]=[0.75,$ 0.25]$

Step-by-step explanation:

The matrix below shows the transition probabilities of the state of the system.

$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

(a)To determine the probability of the system being down or running after any k hours, we determine the kth state matrix $P^k$ .

(a)

$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

is 0.588.

(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

4 0

4 years ago

Write and solve an equation for the following word problem. Define your variable.

marshall27 [118]

Answer:

The variable is the number of clothes sold 'x'.

The equation is: $118.50=100+0.25x$

The number of clothes sold by Lynn are 74.

Step-by-step explanation:

Let the number of pieces of clothes sold be 'x'.

Given:

Earning of Lynn per cloth is $0.25.

Fixed earning of Lynn per day is $100

Total earning after selling 'x' clothes is $118.50.

Variable: Number of clothes 'x'.

Equation:

Earning of Lynn for 1 cloth = $0.25

∴ Earning of Lynn for 'x' clothes = $0.25\times x=0.25x$

Now, total earning of Lynn is the sum of fixed earning and earning from selling 'x' clothes. Therefore,

Total earning = Fixed earning + Earning for 'x' clothes

⇒ $118.50=100+0.25x$

Solution:

Add -100 both sides and then divide the result by 0.25 both sides. This gives,

$118.50-100=100-100+0.25x\\0.25x=18.50\\x=\frac{18.50}{0.25}=74$

Therefore, the number of clothes sold by Lynn are 74.

3 0

4 years ago

If there were 7 times as many of each color car in the parking lot, how

dangina [55]

The answer is 441 by multiplying the number of red cars with 7

7 0

3 years ago

Read 2 more answers

Bob was driving home at an average speed of 40mph for 2 hours. How fast should he drive for the next 1 hour to have an average s

Aleks04 [339]

Answer:

He will need to drive 70 mph for the next hour for his average to be 50pmh.

Hope this helped :)

3 0

3 years ago