Answer:
![s = 11](https://tex.z-dn.net/?f=s%20%3D%2011)
Explanation:
Given
The attachment completes the question.
Required
Find s
Because ABCD and EFGH are similar, then:
![\frac{AB}{CD} = \frac{EF}{GH}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7BCD%7D%20%3D%20%5Cfrac%7BEF%7D%7BGH%7D)
From the attachment:
![AB = 2s](https://tex.z-dn.net/?f=AB%20%3D%202s)
![CD = 3s - 3](https://tex.z-dn.net/?f=CD%20%3D%203s%20-%203)
![EF = 5.5](https://tex.z-dn.net/?f=EF%20%3D%205.5)
![GH = 7.5](https://tex.z-dn.net/?f=GH%20%3D%207.5)
So, we have:
![\frac{2s}{3s - 3} = \frac{5.5}{7.5}](https://tex.z-dn.net/?f=%5Cfrac%7B2s%7D%7B3s%20-%203%7D%20%3D%20%5Cfrac%7B5.5%7D%7B7.5%7D)
Cross Multiply
![2s * 7.5 = 5.5(3s - 3)](https://tex.z-dn.net/?f=2s%20%2A%207.5%20%3D%205.5%283s%20-%203%29)
Open bracket
![2s * 7.5 = 5.5*3s - 5.5*3](https://tex.z-dn.net/?f=2s%20%2A%207.5%20%3D%205.5%2A3s%20-%205.5%2A3)
![15s = 16.5s - 16.5](https://tex.z-dn.net/?f=15s%20%3D%2016.5s%20-%2016.5)
Collect Like Terms
![15s - 16.5s = - 16.5](https://tex.z-dn.net/?f=15s%20-%2016.5s%20%3D%20-%2016.5)
![-1.5s = - 16.5](https://tex.z-dn.net/?f=-1.5s%20%3D%20-%2016.5)
Make s the subject:
![s = \frac{-16.5}{-1.5}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B-16.5%7D%7B-1.5%7D)
![s = \frac{16.5}{1.5}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7B16.5%7D%7B1.5%7D)
![s = 11](https://tex.z-dn.net/?f=s%20%3D%2011)
<em>Hence, the value of s is 11 m</em>
Answer:
hello you noob bsdk har mahadev ka hai to thoda aur bta bro and then give us an Indian I am not sure if you have to leave clan of
Well, from what I know, I believe that it does not. I don't see how it's possible, if y = 7, how does this relate to (0,1), I don't see how it's would be possible. My guess, it would impossible.
Answer:
D) Molecules move from areas of high concentration to areas of low concentration.
Explanation:
Answer:
B. CH₅N
Explanation:
The combustion reaction of a compound CₐHₓNₙ with O₂ is:
CₐHₓNₙ + O₂ → a CO₂ + X/2 H₂O + n NO₂
Where 1 mole of CₐHₓNₙ with an excess of O₂ produce a moles of CO₂, X/2 moles of H₂O and n moles of NO₂
Thus, you need to convert the mass of CO₂ and H₂O to moles to find the C:H ratio and determine a possible empirical formula thus:
Moles CO₂ (Molar mass 44g/mol):
44g ₓ (1mol / 44g) = 1 mole CO₂ = 1 mole C
Mole of H₂O (Molar mass 18g/mol):
45g ₓ (1 mol / 18g) = 2.5 moles H₂O = 5 moles H
Thus, in the compound you have 5 moles of H per mole of C, and a possible empirical formula is:
B. CH₅N
The only structure that meet this C:H ratio