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3 years ago

- Что общего между фантастическим рассказом и сказкой? А чем они отличаются?

SAT

2 answers:

Alexeev081 [22]3 years ago

7 0

1-фантастика и сказка в том что действия происходят в неком в неизведонном пространстве среди разных героев

2-Алиса смешная любопытная и обожает путешествие.3-??

elena-14-01-66 [18.8K]3 years ago

6 0

Answer:no entiendo el idioma

Explanation:podias traducirlo

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A child riding a bicycle at 15 m/s accelerates at 3. 0 m/s/s for 4. 0 s. What is the child's speed at the end of this 4. 0 s int

mamaluj [8]

Answer:

The final speed of bicycle would be 27 m/s².

Step-by-step explanation:

Given :

$\small\red\bull$ Initial velocity (u) = 15 m/s
$\small\red\bull$ Acceleration (a) = 3.0 m/s²
$\small\red\bull$ Time = 4 seconds

To Find :

$\small\red\bull$ Final velocity (v)

Using Formula :

$\longrightarrow{\pmb{\sf{v = u + at}}}$

$\small\blue\star$ v = final velocity
$\small\blue\star$ u = initial velocity
$\small\blue\star$ a = acceleration
$\small\blue\star$ t = time taken

Solution :

Substituting the values in the formula to find the final velocity :

$\longrightarrow{\sf{v = u + at}}$

$\longrightarrow{\sf{v = 15 + (3.0 \times 4)}}$

$\longrightarrow{\sf{v = 15 + (3 \times 4)}}$

$\longrightarrow{\sf{v = 15 +(12)}}$

$\longrightarrow{\sf{v = 15 +12}}$

$\longrightarrow{\sf{v = 27 \: {m/s}^{2}}}$

$\star{\underline{\boxed{\red{\sf{v = 27 \: {m/s}^{2}}}}}}$

Hence, the final speed of bicycle would be 27 m/s².

$\rule{300}{1.5}$

3 0

3 years ago

Identify the reference angle es001-1. Jpg for each given angle, es001-2. Jpg. Es001-3. Jpg degrees. Es002-1. Jpg degrees. Es003-

julia-pushkina [17]

The reference angle is the smallest angle between the terminal side and the x-axis.

$(1)\ \theta = 300^o$

300 degrees is in the 4th quadrant.

So, the reference angle is

$\alpha = 360 - \theta$

$\alpha = 360 - 300$

$\alpha = 60^o$

Hence, the reference angle of 300 degrees is 60 degrees

$(2)\ \theta = 225^o$

225 degrees is in the 3rd quadrant.

So, the reference angle is

$\alpha = \theta - 180$

$\alpha = 225 - 180$

$\alpha = 45^o$

Hence, the reference angle of 225 degrees is 45 degrees

$(3)\ \theta = 480^o$

480 degrees is in the 2nd quadrant (i.e. 480 - 360 = 120)

So, the reference angle is

$\alpha = 180 - \theta$

$\alpha = 180 - 120$

$\alpha = 60^o$

Hence, the reference angle of 480 degrees is 60 degrees

$(2)\ \theta = -210^o$

-210 degrees is in the 2nd quadrant (i.e. 360 - 210 = 150)

So, the reference angle is

$\alpha = 180 - \theta$

$\alpha = 180 - 150$

$\alpha = 30^o$

Hence, the reference angle of -210 degrees is 30 degrees

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