PLEASE HELP ME!!!!!!

Need an answer for both plez.

Ilya [14]

Answer:

(2, 13)

Step-by-step explanation:

Since they both equal y, you can equal them to each other.

8x - 3 = 2x + 9

Subtract 2x from both sides.

6x - 3 = 9

Add 3 to both sides.

6x = 12

Now divide 6 on both sides.

x = 2

Now that we have found x, we need to find y. Just plug in x to the equations.

y = 2(2) + 9

y = 4 + 9

y = 13

Now, if the next equal has the same y, then both are true.

8(2) -3 = y

16-3=y

13 = y

So therefor, both x and y are true.

3 0

3 years ago

WHAT IS THE DOMAIN OF (F+G) (X) ?

trapecia [35]

Are the x values of the given function of (F+G)(X)./

7 0

4 years ago

Two catalysts may be used in a batch chemical process. Twelve batches were prepared using catalyst 1, resulting in an average yi

aalyn [17]

Answer:

a) $t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

$df=12+15-2=25$

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) $(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

Step-by-step explanation:

Notation and hypothesis

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

This last one is an unbiased estimator of the common variance $\sigma^2$

Part a

The system of hypothesis on this case are:

Null hypothesis: $\mu_2 \leq \mu_1$

Alternative hypothesis: $\mu_2 > \mu_1$

Or equivalently:

Null hypothesis: $\mu_2 - \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 > 0$

Our notation on this case :

$n_1 =12$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =85$ represent the sample mean for the group 1

$\bar X_2 =91$ represent the sample mean for the group 2

$s_1=3$ represent the sample standard deviation for group 1

$s_2=2$ represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

$\S^2_p =\frac{(12-1)(3)^2 +(15 -1)(2)^2}{12 +15 -2}=6.2$

And the deviation would be just the square root of the variance:

$S_p=2.490$

Calculate the statistic

And now we can calculate the statistic:

$t=\frac{(91-85)-(0)}{2.490\sqrt{\frac{1}{12}}+\frac{1}{15}}=6.222$

Now we can calculate the degrees of freedom given by:

$df=12+15-2=25$

Calculate the p value

And now we can calculate the p value using the altenative hypothesis:

$p_v =P(t_{25}>6.222) =8.26x10^{-7}$

Conclusion

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Part b

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

For the 99% of confidence we have $\alpha=1-0.99 = 0.01$ and $\alpha/2 =0.005$ and the critical value with 25 degrees of freedom on the t distribution is $t_{\alpha/2}= 2.79$

And replacing we got:

$(91-85) -2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =3.309$

$(91-85) +2.79 *2.490 \sqrt{\frac{1}{12} +\frac{1}{15}} =8.691$

7 0

3 years ago

What is the equation of the line

konstantin123 [22]

Hello there!

The answer is B. $\frac{2}{7}$
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Explanation and Work:

We first must identify if the line goes through the origin or not.

The origin is (0, 0)

The line does go through the origin. This means that there is no y-intercept

The specific equation we would you use would be:

y = kx

K is the constant

We find this by finding the slope.

Slope is found by:

$\frac{y2 - y1}{x2 - x1}$

y2 = 2

y1 = 0

x2 = 7

x1 = 0

Now, let's plug in these numbers.

$\frac{2-0}{7-0} = \frac{2}{7}$

So, now let's plug he slope into our formula.

y = $\frac{2}{7} x$

So, our answer would be B.

I hope I helped!

Let me know if you need anything else!

~ Zoe

8 0

3 years ago

Help, this is a really challenging IXL!

snow_lady [41]

Answer:

in 4/5 fraction of the game they scored two or more runs.

3 0

3 years ago