Answer:
Explanation:
The following code is written in Java and modified to do as requested. It asks the user to enter a number that is saved to the amountToChange and then uses the % operator to calculate the number of 5 dollar bills and the number of 1 dollar bills to give back. A test case has been provided and the output can be seen in the attached image below.
import java.util.Scanner;
class ComputingChange {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int amountToChange;
int numFives;
int numOnes;
amountToChange = scnr.nextInt();
numFives = amountToChange / 5;
/* Your solution goes here */
numOnes = amountToChange % 5;
System.out.print("numFives: ");
System.out.println(numFives);
System.out.print("numOnes: ");
System.out.println(numOnes);
}
}
Answer:
a) to persuade
she is doing this to propose an idea to the boss of the company
Answer:
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Explanation:
flwgrweg
Answer:
// code to read grade
#include <stdio.h>
// main function
int main(void) {
// if grade is character
char grade;
// if grade is numeric then we can use int or double
// int grade;
// double grade;
printf("Enter your grade:");
// read grade from user
scanf("%c",&grade);
// print grade
printf("your grade is:%c",grade);
return 0;
}
Explanation:
To read a value, scanf() function is used from stdio.h.Read a grade from user and assign it to variable "grade".
Output:
Enter your grade:A
your grade is:A
// code to read die volt
#include <stdio.h>
// main function
int main(void) {
// variable
double die_volt;
printf("Enter die volt:");
// read die volt from user
scanf("%lf",&die_volt);
// print die volt
printf("Entered die volt is:%0.2lf",die_volt);
return 0;
}
Explanation:
Read the die volt from user and assign it to variable "die_volt" with the help
of scanf() function.
Output:
Enter die volt:220
Entered die volt is:220.00
1. 3 times the light voltage, ie., 3*0.5 = 1.5V
2. Total R = 3*25 = 75Ω, V=1.5V, I = V/R = 1.5/75 = 20 mA
3. A 1.5V battery (e.g., an AA battery) with a charge of at least 20mAh. AA batteries should be able to handle this easily.
