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3 years ago

Both the ranges and the interquartile ranges for the data sets are the same.

Mathematics

1 answer:

aleksley [76]3 years ago

6 0

Answer:

to find range of interquartile sets of data

you see 5 vertical lines 1 is start point 2 is start of 2nd quartile 3 is start of 3rd quartile and also represents the median. the 4th start of 4th quartile and 5th is very end point.

Therefore the interquartile is from start line 2 to start line 4

apply to each by if it says 10 and 34 then we show workjings 34-10 = 24 and that is the range once we deduct data from each other.

Therefore full range is start line 1 to end line 5

if this says 2 to 45 then full range is 45-2 = 43 and apply to each boxplot.

Step-by-step explanation:

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50 POINTS PLEASE HELP

lorasvet [3.4K]

Answer:

$perimeter= 5\sqrt{15} + 5\sqrt{5}$

Step-by-step explanation:

Given ,

A right angle triangle ΔABC with right angle at C and ∠A=30° and AC=5√5 units .

Let ∠A=A,∠B=B∠C=C and AC=b,BC=a,CA=b .

Implies perimeter of triangle = a+b+c .

now

$tanA=\frac{a}{b} \\\a=b*tanA\\a= 5\sqrt{5} *tan30^0\\a=\frac{5\sqrt{5}}{\sqrt{3}}$

and

$cosA=\frac{b}{c} \\\c=\frac{b}{cosA} \\c=\frac{10\sqrt{5}}{\sqrt{3} }$

implies ,

$perimeter = \frac{5\sqrt{5}}{\sqrt{3}} + 5\sqrt{5} +\frac{10\sqrt{5}}{\sqrt{3} }\\perimeter= 5\sqrt{15} + 5\sqrt{5}$

8 0

3 years ago

Read 2 more answers

Write each ratio as a rate.

Setler [38]

Answer:

a. 62 miles/hour

b. 1.25 laps/minute

Step-by-step explanation:

a. ratio of miles to the number of hours is 434 to 7 can also be written as

$\frac{434}{7}$ = 62 miles/hour

therefore rate or speed= 62 miles/hour

b. $\frac{number\ of \ laps}{number\ of \ minutes} = \frac{5}{4}$

= 1.25 laps/minute which rate or speed

7 0

3 years ago

Simplify the expression using order of operation 5 x 2 + 3 to the power of 2

TiliK225 [7]

answer= 1

5 x 2 - 3^2

1. First simplify exponents

= that is nine

2. Then Do 5 x 2- 9

5 x 2=10

10-9

= 1

6 0

3 years ago

What is the slop of y=-7

AlladinOne [14]

Answer:

slope of y = -7 is 0

Step-by-step explanation:

y = any number forms a graph of a horizontal line

x = any number forms a graph of a vertical line

For any horizontal line , the slope is always 0

for any vertical line , the graph is always undefined

So for y =-7 we will get a horizontal line at -7 on t

the slope of horizontal line y=-7 is 0

3 0

3 years ago

Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=

Genrish500 [490]

Answer:

$f'''(x)=\frac{3}{x^{2}}$

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

$f''(x)=9-\frac{3}{x}$

We need to find Third-order derivative of the function f(x).

$f''(x)=9-\frac{3}{x}=9-3x^{-1}$

We know that,

f'''(x) = (f''(x))'

So,

$f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}$

$f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}$

$f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}$

$f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}$

$f'''(x)=-3(-1)x^{-1-1}$

$f'''(x)=3x^{-2}$

$f'''(x)=\frac{3}{x^{2}}$

Therefore, $f'''(x)=\frac{3}{x^{2}}$

4 0

4 years ago