Answer:
the answer i think is DMR
Step-by-step explanation:
because u use the letters from the corners
Answer:
-4,-5/2
Step-by-step explanation:
2x^2+3x-20 =0
2x^2+8x-5x-20 =0
2x(x+4)-5(x+4) =0
(x+4)(2x-5) =0
Either,
x+4=0
x=-4
Or,
2x-5=0
2x=5
x=5/2
n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
-----------------------------------------------------
ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
----------------------------------------------------------
n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
