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miskamm [114]
3 years ago
13

Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.

Mathematics
1 answer:
jek_recluse [69]3 years ago
4 0

Answer:

Choice B: y = 2\, (x - 6)^{2} + 5.

Step-by-step explanation:

For a parabola with vertex (h,\, k), the vertex form equation of that parabola in would be:

\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}.

In this question, the vertex is (6,\, 5), such that h = 6 and k = 5. There would exist a constant a such that the equation of this parabola would be:

y = a\, (x - 6)^{2} + 5.

The next step is to find the value of the constant a.

Given that this parabola includes the point (7,\, 7), x = 7 and y = 7 would need to satisfy the equation of this parabola, y = a\, (x - 6)^{2} + 5.

Substitute these two values into the equation for this parabola:

7 = (7 - 6)^{2}\, a + 5.

Solve this equation for a:

7 = a + 5.

a = 2.

Hence, the equation of this parabola would be:

y = 2\, (x - 6)^{2} + 5.

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<span>1.
"The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x"

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3.

If John's limit is $60,000, his monthly income is 

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instead of g(x), we could use the notation </span>f ^{-1}(x)<span>



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