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4 years ago

Solve 11kx + 13kx = 6 for x. A. X= 1/4k B. X= 4k C. X= 4/k D. X= k/4

Mathematics

2 answers:

mixer [17]4 years ago

8 0

Answer:

Option (a) is correct.

$x=\frac{1}{4k}$

Step-by-step explanation:

Given: Equation 11kx + 13kx = 6

We have to solve for x and choose the correct option from the given options.

Consider the given equation 11kx + 13kx = 6

Taking kx common, we have,

kx (11+13) = 6

Simplify, we have,

24kx = 6

Divide both side by 24, we have,

$kx=\frac{6}{24}$

Simplify, we have,

$kx=\frac{1}{4}$

Divide both side by k, we have,

$x=\frac{1}{4k}$

Thus, Option (a) is correct.

rjkz [21]4 years ago

3 0

24kx = 6
kx = 6/24
kx = 1/4
x = 1/4/k
x = 1/4k

Answer: A) X = 1/4k or the first option.

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Charles wants to take out a 5 year loan on a car that costs $15,000. He is trying to make a rough estimate to decide if he can a

marin [14]

Answer:

No, This is not reasonable estimate.

Step-by-step explanation:

Charles wants to take out a 5 year loan on car that cost $15000.

He make rough estimate to make payment. He can afford to pay up to $200 per month.

First we find total number of months in 5 years.

Total months = 5x12= 60 months

Total estimate to pay = $60\times 200$ =$12000

we can see cost of a car $15,000 is greater than his estimation $12,000.

Therefore, Charles estimation will not work.

No, This is not reasonable estimate.

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3 years ago

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. Determ

Hunter-Best [27]

Answer:

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not.

This means that $n = 100, \pi = \frac{20}{100} = 0.2$

68% confidence level

So $\alpha = 0.32$ , z is the value of Z that has a pvalue of $1 - \frac{0.32}{2} = 0.84$ , so $Z = 0.995$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.16$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.24$

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

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3 years ago

Definition of uniform speed

iren2701 [21]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

The following lines are parallel. 2x + 2y = 4 and y = -x + 5 true false

enot [183]

False because its the right choice

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3 years ago

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. A shipyard makes a container ship that can withstand the total amount of weight W, which is normally distributed with mean of

Debora [2.8K]

Answer:

the maximum number of containers that the ship can load is 170

Step-by-step explanation:

Given the data in the question;

W ~ N( 600, 60 )

S ~ N( 4n, 0.4√n )

p( W > S ) = 0.90

⇒ P( W - S > 0) = 0.9 ------ let this be equation 1

now, since W and S are independent

Mean( W - S ) = Mean( W ) - Mean( S 0 = 600 - 4n

and

SD( W - S ) = √( var(W) + var(S) ) = √( 60² + 0.4²n)

hence;

W - S ~ N( 600 - 4n, √( 60² + 0.4²n) )

now, from equation one, P( W - S > 0) = 0.9

$P( \frac{(W-S)-Mean(W-S)}{SD(W-S)} > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = 0.90$

$P( z > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = 0.90$

from z- table

$P( z > \frac{0-(600-4n)}{\sqrt{60^2 + 0.4^2n} }) = P( z >-1.282)$

$\frac{4n - 600}{\sqrt{60^2 + 0.4^2n} } = -1.282$ ------------------ let this be equation 2

now, we square both sides of equation 2

$\frac{(4n - 600)^2}{60^2 + 0.4^2n} } = (-1.282)^2$

$\frac{(4n - 600)(4n-600)}{3600 + 0.16n} } = 1.643524$

we cross multiply

16n² + 360000 - 4800n = 1.643524( 3600 + 0.16n )

16n² + 360000 - 4800n = 5916.6864 + 0.26296384n

16n² + 360000 - 5916.6864 - 4800n - 0.26296384n = 0

16n² + 354083.3136 - 4800.26296384n = 0

16n² - 4800.26296384n + 354083.3136 = 0

solving the quadratic equation, we know that;

x = -b±√( b² - 4ac ) / 2a

so we substitute

x = [-(-4800.26296384) ±√( (-4800.26296384)² - (4 × 16 × 354083.3136)] / [2×16]

x = [ 4800.26296384 ±√( 23042524.522 - 22661332.0704 ] / 32

x = [ 4800.26296384 ±√(381192.4516) ] / 32

x = [ 4800.26296384 ± 617.4078 ] / 32

Hence;

x = [ 4800.26296384 - 617.4078 ] / 32 or [ 4800.26296384 + 617.4078 ] / 32

x = 131 or 170

Therefore, the maximum number of containers that the ship can load is 170

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3 years ago