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Anna71 [15]
2 years ago
12

Translate the sentence into an equation. Four times the difference of a number and 5 is 24.

Mathematics
1 answer:
uranmaximum [27]2 years ago
6 0
Correct!!! ♥ good job




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HELP ME LLEASE WUIZ OMG WHAT ARE THE CORDS? 30 points
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Answer: -1/2 and 1/3

Step-by-step explanation:

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3 years ago
Need this urgently!! Please help me
Gemiola [76]
Flower bed A:
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3 years ago
Which of the following shows the extraneous solution to the logarithmic equation below? log Subscript 3 Baseline (18 x cubed) mi
Mnenie [13.5K]

Answer:

C.) x= -4

Step-by-step explanation:

just took the test on edg. 2020

3 0
3 years ago
Read 2 more answers
Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

8 0
3 years ago
Which of the following are identities? Check all that apply. A. cot2x + 1 = csc2x B. tan2x = 1 - sec2x C. sin2x = 1 + cos2x D. s
kirill115 [55]

I'll assume those are squares.  We know D is an identity:

\sin^2 x + \cos ^2 x = 1

Dividing through by \sin ^2 x

1 + \cot^2 x = \csc^2 x

That's A.

Dividing the original through by \cos ^2 x

\tan^2 x + 1 = \sec^2 x

Not quite B, wrong sign on tangent.  

C has the wrong sign on cosine squared as well.

Identities: A & D
4 0
3 years ago
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