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aleksandrvk [35]
3 years ago
15

What variable is isolated? _____

Mathematics
2 answers:
ololo11 [35]3 years ago
5 0
I think the Answer is the variable X
FromTheMoon [43]3 years ago
3 0
Put every term that contains the variable on one side of the equation<span> and every term that does not contain a variable on the other side. Divide both sides of the </span>equation<span> by the coefficient – the number attached to the variable. Solve for x. The solution is x = 4.</span>
You might be interested in
Help me ASAP
KonstantinChe [14]

2 * 4 = 8

8 < 11 is true

2 * 5 = 10

10 < 11 is true

2 * 5.3 =  10.6

10.6 < 11 is true

2 * 5.7 = 11.4

11.4 < 11 is NOT true.

x = 5.7 is not a solution.

3 0
3 years ago
Read 2 more answers
Solve the linear equation: <br><br> <img src="https://tex.z-dn.net/?f=4%5E%7B2x%2B7%7D%20%3D%208%5E%7B2x-3%7D" id="TexFormula1"
g100num [7]

Answer:

  x = 11.5

Step-by-step explanation:

Taking the logarithm base 2 will transform this to a linear equation.

  2(2x+7) = 3(2x -3)

  0 = 3(2x -3) -2(2x +7) . . . . subtract the left side

  0 = 2x -23 . . . . . . . . . . . . . simplify

  0 = x - 23/2 . . . . . . . . . . . . divide by 2

  11.5 = x . . . . . . . . . . . . . . . . add 11.5

The solution is x = 23/2 = 11.5.

_____

<em>Check</em>

This value of x makes the equation become ...

  4^(2·23/2 +7) = 8^(2·23/2 -3)

  4^30 = 8^20 . . . . . true

8 0
4 years ago
Drag each tile to the correct box. A data set that consists of many values can be summarized using the five-number summary. Arra
dimaraw [331]

Answer:

Minimum < Q1 < Median < Q3< Maximum

Step-by-step explanation:

Given

Minimum, Median, Maximum, Q3 and Q1

<em>See attachment for complete question</em>

Required

Order from least to greatest

In a dataset, the range is:

Range = Maximum - Minimum

This implies that, the minimum is the least and the maximum is the highest of the dataset

So, we have:

Minimum <         <              <           < Maximum

The median is the middle item; So, the above becomes

Minimum <         < Median <           < Maximum

In a dataset, the IQR is:

IQR = Q_3 - Q_1

This implies that:

Q_3 > Q_1

So, we have:

Minimum < Q1 < Median < Q3< Maximum

6 0
3 years ago
. can someone help pls
disa [49]

Answer:

The answer is 3,906.25

Step-by-step explanation:

All you have to do is divide 15,625 by 4! :)

6 0
3 years ago
Pls help, thanks for the answer thanks
siniylev [52]
A. Length: 7, Width: 5
B. Perimeter: 24
C. Area: 35
4 0
3 years ago
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