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gizmo_the_mogwai [7]
3 years ago
15

Complete the first 4 steps for graphing the quadratic function given.

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

To be honest, I'm not sure which four steps your teacher is referring to. However, I'll show you one way to graph this.

A graph is simply a collection of points. Often those points are connected in some way (though they don't necessarily have to be) to form a curve.

Each point is of the form (x,y). To get each point, we pick random x values and determine their paired y value counterpart.

For example, if we pick x = -3, then,

y= -x^2 -4x -3

y= -(-3)^2 -4(-3) -3

y = -9 - 4(-3) - 3

y = -9 + 12 - 3

y = 0

This indicates that (-3, 0) is one point on the curve.

Let's repeat for x = -2

y= -x^2 -4x -3

y= -(-2)^2 -4(-2) -3

y = -4 - 4(-2) - 3

y = -4 + 8 - 3

y = 1

So (-2, 1) is another point on the curve.

Repeat this process as many times as you want. You should do at least 3 or 4 points in my opinion. The more points you generate, the more accurate the curve. After generating the points, you'll plot them all on the same xy grid. Then finally draw a curve through all of the points as shown below.

I used GeoGebra to make the graph.

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10 subtracted from the quotient of a number and -3 is at least -1​
Mazyrski [523]

<em><u>10 subtracted from the quotient of a number and -3 is at least -1​ is:</u></em>

\left(\frac{x}{-3}\right)-10\ge \:-1\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-27\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-27]\end{bmatrix}

<em><u>Solution:</u></em>

<em><u>Given statement is:</u></em>

10 subtracted from the quotient of a number and -3 is at least -1​

Quotient means reuslt of dividing two numbers

Let the number be "x"

quotient of a number and -3 = \frac{x}{-3}

Therefore,

10 subtracted from \frac{x}{-3} is at least -1

at least means "less than or equal to"

<em><u>Which is translated into algebraic expression as:</u></em>

(\frac{x}{-3}) - 10\geq -1

<em><u>Solve the above inequality</u></em>

\left(\frac{x}{-3}\right)-10\ge \:-1\\\\\mathrm{Add\:}10\mathrm{\:to\:both\:sides}\\\\\frac{x}{-3}-10+10\ge \:-1+10\\\\\mathrm{Simplify}\\\\\frac{x}{-3}\ge \:9\\\\Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

When we multiply or divide by negative number. we have to flip the inequality sign

\frac{x\left(-1\right)}{-3}\le \:9\left(-1\right)\\\\\mathrm{Simplify}\\\\\frac{x}{3}\le \:-9\\\\\mathrm{Multiply\:both\:sides\:by\:}3\\\\\frac{3x}{3}\le \:3\left(-9\right)\\\\\mathrm{Simplify}\\\\x\le \:-27

Thus the solution of inequality is found

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