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ki77a [65]
3 years ago
15

Slope of the line 8x+6y=12

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0
The slope

Of the line is -4/3
ICE Princess25 [194]3 years ago
4 0
The slope

 is -4/3...........
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12p + 7 > 139 greater or less than
bazaltina [42]

Answer:

\Huge \boxed{p>11}

Step-by-step explanation:

First, subtract by 7 both sides of equation.

\displaystyle 12p+7-7>139-7

Solve.

\displaystyle 139-7=132

12p>132

Then, divide by 12 both sides of equation.

\displaystyle \frac{12p}{12}=\frac{132}{12}

Solve to find the answer.

\displaystyle 132\div12=11

\huge \boxed{p>11}, which is our answer.

3 0
3 years ago
Square root of 9/100
timama [110]
\sqrt{ \frac{9}{100} }
=\frac{3}{10}
5 0
3 years ago
Helpppppp helpppppppp plssssssssss
Vinil7 [7]

Answer:

Scales-No equal sides

Isosceles- 2 Equal

Equilateral-

Right-90 degree

Obtuse- Obtuse Angle

8 0
3 years ago
Worth 75 points!! Need help with calculus
Keith_Richards [23]
The correct answer is:

2u-v=7(5i-3j)

Therefore, 5, and 3 go inside the box.
4 0
3 years ago
Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0
1 year ago
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