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4vir4ik [10]
3 years ago
8

What is m∠A ? Enter your answer in the box. ° Triangles A B E and D C E share vertex E. Angle B is 18 degrees. Angle C is 43 deg

rees. Angle D is 35 degrees.

Mathematics
2 answers:
Allisa [31]3 years ago
5 0

Answer: The measure of angle A is 60 degree.

Explanation:

It is given that the Triangles A B E and D C E share vertex E. Angle B is 18 degrees. Angle C is 43 degrees. Angle D is 35 degrees.

According to angle sum property, the sum of angles of a triangle is always 180 degree.

In triangle CDE,

\angle ECD+\angle CDE+\angle DEC=180^{\circ}

43^{\circ}+35^{\circ}+\angle DEC=180^{\circ}

78^{\circ}+\angle DEC=180^{\circ}

\angle DEC=180^{\circ}-78^{\circ}

\angle DEC=102^{\circ}

According to opposite vertical angle property.

\angle AEB=\angle DEC

\angle AEB=102^{\circ}

Use angle sum property is triangle ABE.

\angle ABE+\angle BEA+\angle EAB=180^{\circ}

\angle ABE+102^{\circ}+18^{\circ}=180^{\circ}

\angle ABE+120^{\circ}=180^{\circ}

\angle ABE=60^{\circ}

Therefore, the measure of angle A is 60 degree.

borishaifa [10]3 years ago
5 0

Answer:

60 degrees

Step-by-step explanation:

It is given that the Triangles A B E and D C E share vertex E. Angle B is 18 degrees. Angle C is 43 degrees. Angle D is 35 degrees.

According to angle sum property, the sum of angles of a triangle is always 180 degree.

In triangle CDE,

According to opposite vertical angle property.

Use angle sum property is triangle ABE.

Therefore, the measure of angle A is 60 degrees

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3 years ago
5. Add (-6-22) + (-3 2 1).<br> A.-[903]<br> B-[303]<br> C-[603]<br> D.-9-3-5
Scorpion4ik [409]
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6 0
3 years ago
A machine fills containers with a particular product. Assume the filling weights are normally distributed with a variance of 0.1
Ghella [55]

Answer:

z=-0.674

And if we solve for \mu we got

\mu=12 +0.674*0.4=12.270

So then the mean is 'mu = 12.270 for this case.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sqrt{0.16}= 0.4)  

For this part we want to find a value a, such that we satisfy this condition:

P(X>12)=0.85   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.85 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.85

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for \mu we got

\mu=12 +0.674*0.4=12.270

So then the mean is 'mu = 12.270 for this case.

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3 years ago
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Arturiano [62]
The match started at 1450 hours.
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1 year ago
PLEASE HELP!
m_a_m_a [10]
I hope this helps you

3 0
3 years ago
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