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2 years ago

What is the ratio of 6 and 45

Mathematics

2 answers:

stepan [7]2 years ago

8 0

I’m having a hard time understanding your question

Arte-miy333 [17]2 years ago

7 0

Divide 45 by 6 then multiply find out the half ratio

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Suppose calls are arriving at a telephone exchange at an average rate of one per second, according to a Poisson arrival process.

antoniya [11.8K]

Answer:

Explanation has been given below

Step-by-step explanation:

a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.

probability distribution function is F(t)=n*exp(-n*t).

reference to any kth packet and the (k-1)th packet

the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)

b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)

probability of fourth call within t=5 seconds is =

that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.

c) number of calls/rate = 4/n = 4 seconds

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2 years ago

At the end of each year, how much money would you earn in interest if you invested $3,500 and earned 4.5% simple interest?

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$157.50 would be the amount that you earn in interest

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3 years ago

Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n

konstantin123 [22]

Answer:

a) $P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

b) $P(13.848$ Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by $S^2$ and we select a random sample of size n from a normal population with a population variance $\sigma^2$ . And we define the following statistic:

$T = \frac{(n-1) S^2}{\sigma^2}$

And the distribution for this statistic is $T \sim \chi^2_{n-1}$

For this case we know that n =25 and $\sigma^2 = 6$ so then our statistic would be given by:

$\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2$

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

$P(S^2 > 9.1)$

And we can multiply the inequality by 4 on both sides and we got:

$P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502$

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

$P(3.462 < S^2$

If we multiply the inequality by 4 on all the terms we got:

$P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2$ And we can find this probability like this: $P(13.848$ And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"