I think it is D. not sure tho
Answer:
Sorry the screenshot is black but i would like to help if you can repost, it?
Step-by-step explanation:
Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
Answer:
4(x - 3)
Step-by-step explanation:
When you put brackets around a binomial (has 2 parts separated by a plus / - sign), you must take out a common factor from both terms separated by the + or - sign
A only has the 4 taken away from the x. The answer is not A
B has the 3 removed from the 12, not the x, so B is not the answer.
C that's the answer.
12.5/100 = 0.125
Basically division
