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Pavlova-9 [17]
3 years ago
7

Write the equation for a line that passes through the point (2,5) and a slope of m =10 in point slope form

Mathematics
2 answers:
wlad13 [49]3 years ago
8 0

Answer:

y=10x-15

Step-by-step explanation:

with the points given you know x=2 and y=5

make a new point called (x,y)

now use the formula (y-5)/(x-2)=10 (10 being the gradient)

y-5 = 10(x-2)

y-5=10x-20

add 5 to both sides

y-5+5=10x-20+5

y=10x-15

Tatiana [17]3 years ago
7 0

Since we're given a point and a slope, we can write

the equation of this line using the point-slope formula.

The point-slope formula is shown at the top of the image below.

The given point, (2,5), represents (x1,y1).

Now plug in the information to get the equation below.

Now you can distribute the 10.

Then add 5 to both sides.

You will end up with the equation y = 10x - 15 as your answer.

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Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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