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podryga [215]
3 years ago
10

Triangle D E F is shown. Angle D E F is 140 degrees. The length of D E is 11, the length of E F is 9, and the length of D F is e

.
In ΔDEF, DE = 11, EF = 9, and angle E = 140°.



Which equation correctly uses the law of cosines to solve for the third side?

e2 = 112 + 92 − 2(11)(9)cos(140°)
112 = e2 + 92 − 2e(9)cos(140°)
92 = e2 + 112 − 2e(11)cos(140°)
e = 11 + 9 − 2(11)(9)cos(140°)
Mathematics
2 answers:
AnnyKZ [126]3 years ago
4 0

Answer:

e2 = 112 + 92 − 2(11)(9)cos(140°)

Anna [14]3 years ago
4 0

Answer:

A

Step-by-step explanation:

2020 Edge

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Answer:

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Step-by-step explanation:

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SO then your equation should look like this:

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The answer to the question is no because in order for this to work it would need to be the greater than or equal to sign, which looks like this ≥.

Hope this helps and have a great day! :)

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See image for details on question
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7 0
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