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Karolina [17]
3 years ago
9

4x7/8 will be —————7/8 is it greater than or equal or less than

Mathematics
1 answer:
stellarik [79]3 years ago
7 0
4/1 x 7/8 = 28/8 = 3 4/8 -> 3 1/2.

4 x 7/8 > 7/8 because 4 x 7/8 = 3 1/2 which is larger than 7/8.
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Which of these triangles appear not to be congruent to any other shown here?
Umnica [9.8K]

where is the picture??? Its cant be answered without more info


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The side length of one of the pentagons
rosijanka [135]

Answer: 6.9 and 10.4

Step-by-step explanation:

The perimeter of the pentagon is 10 so you can either do 10 times 1.38 times 1/2 or do 5 times 1.38 and it equals 6.9

The perimeter of the hexagon is 12 and you follow the same steps so I did 6 times 1.73 and you get 10.4

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Find the value of tan F rounded to the nearest hundredth , if necessary
spin [16.1K]

Using it's formula, it is found that the tangent of F is given by:

  • \tan{F} = \frac{6\sqrt{85}}{85}

<h3>How to find the tangent of an angle?</h3>
  • In a right triangle, the tangent of an angle is given by the length of the opposite leg divided by the length of the adjacent leg.

Researching the problem in the internet, it is found that for the <em>right triangle</em> in this problem:

  • The length of the opposite leg to angle F is of 6.
  • The length of the adjacent leg to angle F is of x.
  • The length of the hypotenuse is of 11.

Applying the Pythagorean Theorem, we have that:

6^2 + x^2 = 11^2

36 + x^2 = 121

x^2 = 85

x = \sqrt{85}

Considering that the tangent is the length of the opposite leg divided by the length of the adjacent leg, we have that:

\tan{F} = \frac{6}{\sqrt{85}} \times \frac{\sqrt{85}}{\sqrt{85}} = \frac{6\sqrt{85}}{85}

To learn more about tangent, you can take a look at brainly.com/question/24680641

7 0
3 years ago
Solve for x. <br><br> 4/5(15x+20)−7x=5/6(12x−24)+6<br><br><br><br> Enter your answer in the box.
dmitriy555 [2]
The answer to the question

5 0
3 years ago
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Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
iVinArrow [24]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

8 0
3 years ago
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