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Karolina [17]
3 years ago
9

4x7/8 will be —————7/8 is it greater than or equal or less than

Mathematics
1 answer:
stellarik [79]3 years ago
7 0
4/1 x 7/8 = 28/8 = 3 4/8 -> 3 1/2.

4 x 7/8 > 7/8 because 4 x 7/8 = 3 1/2 which is larger than 7/8.
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A football team won 10 matches out of the total number of matches they played if their win percentage was 40 then how many match
KiRa [710]

Answer:the football team played 25 games in all

Step-by-step explanation:

Let x represent the total number of matches that the football team played.

The football team won 10 matches out of the total number of matches they played. if their win percentage was 40, it means that

10/x × 100 = 40

1000 = 40x

x = 1000/40 = 25

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The box plots show the average gas mileage, in miles per gallon, of cars and minivans tested by a certain company.
mr_godi [17]

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Step-by-step explanation:

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During dance practice, Sasha drank 21⁄2 pints of water, and on the way home she drank 1⁄2 cup of water. How much water did she d
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What is the domain for this relation? Type the numbers in order from least to greatest,
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3 years ago
A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

                                                             = $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

x=\frac{8}{x^{2} }

x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0
3 years ago
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