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3 years ago

WhAt is x if y is n2+x?

Mathematics

1 answer:

Elden [556K]3 years ago

7 0

$y= n^{2} +x \\ x=y-n^{2}$

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(10 points) <br> Solve for x. Assume that the lines which appear to be tangent are tangent

Ganezh [65]

The two tangent lines for each circle are the same length. Set the equations to equal and solve for x.

1. 4x + 3 = 3x +12

Subtract 3x from each side:

x +3 = 12

Subtract 3 from both sides:

x = 9

2. -2 + x = 2x -7

Subtract 2x from both sides:

-2 - x = -7

Add 2 to each side:

-x = -5

Multiply both sides by -1:

x = 5

8 0

3 years ago

Given the triangle below, what is the measure of x to the nearest foot?

luda_lava [24]

Answer:

18 ft

Step-by-step explanation:

Since the triangle is right angled ; we could use trigonometry ;

Using the angle , 40° ; adjacent side, = 14 feets ; hypotenus = x

Cos θ = Adjacent / hypotenus

Cos 40 = 14 / x

0.7660444 = 14 / x

0.7660444x = 14

x = 14 / 0.7660444

x = 18.27

= 18 ( nearest foot)

8 0

2 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ <em>cross multiply</em>

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

5 biscuits cost 40p altogether how much do 3 biscuits cost

STALIN [3.7K]

If 5 biscuits cost 40p

1 biscuit would cost (40p divided by 5) 8p

8p multiplied by 3 (to get 3 biscuits) would cost 24p

3 biscuits cost 24p

7 0

3 years ago

Read 2 more answers

The formula for the volume of w sphere is v=4\3 r3 what is the formula solved for r?

Lyrx [107]

V of w sphere = $\frac{4}{3}$ $\pi$ r³
Multiply by 3 on either sides to get rid of the fraction.
$V * 3 = \frac{4}{3} *3 \pi r^3$
3V = 4 $\pi$ r³
Now divide either sides by 4 $\pi$ to isolate r³
$\frac{3V}{4 \pi } = \frac{4 \pi }{4 \pi }$ r³
4 $\pi$ and 4 $\pi$ cancels out
$\frac{3V}{4 \pi }$ = r³
Take the cube root to isolate r.
$\sqrt[3]{ \frac{3V}{4 \pi } } = \sqrt[3]{r^3}$
the cube root cancels the cube

$\sqrt[3]{ \frac{3V}{4 \pi } }$ = r

6 0

3 years ago