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beks73 [17]
2 years ago
14

Please factor out the following problem:3x^2y^2-xy^2-4y^2

Mathematics
1 answer:
storchak [24]2 years ago
6 0

Answer:

Look at image

Step-by-step explanation:

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URGENT ANSWER ILL MARK BRAINLIEST
Mars2501 [29]

Answer:

x = 7

Step-by-step explanation:

3x - 4 = 2x + 3

3x - 2x = 3 + 4

x = 7.

8 0
3 years ago
Read 2 more answers
A metal rod 9.4 meters long is cut into two pieces. One piece is three times as long as the other. Find the length of the longer
tresset_1 [31]
2a + b = 9.4

There are 3 parts, 2 go to Rod A, 1 go to Rod B.

9.4 / 3 = 3.13333 recurring

Rod A = 2(3.13)
= 6.26

Rod B =
3.13

Rounding, Rod A = 6.3 , Rod B = 3.1
7 0
3 years ago
GUEST, GUEST An airline charges an additional fee for luggage that exceeds the 50-pound weight limit. Drag an arrow to the numbe
Evgesh-ka [11]
To create this inequality graph, you will have an open circle at 50 and an arrow pointing to the right.

Since the bag must be over 50, we draw an open circle at fifty.
Since the fee goes towards the bags over 50, we draw an arrow pointing to the right.
5 0
3 years ago
If the graph of the function f, defined by f(x)= x2 + 5, is translated vertically upward by 2 units, it
otez555 [7]

Answer:

D. k(x)=x²+7

Step-by-step explanation:

f(x)=x² + 5

y=mx+c

since it is not moved horizontally the x and slope(m) will remain the same but the 2 will be added to the intercept(c) which is 5 to become seven

6 0
3 years ago
The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.10
dusya [7]

The distribution is not a standard normal distribution.

We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.

Mathematically:

E(X) = 0 and V(X) = 1

Given that;

  • the mean which follows a normal distribution (X) = 4.5338 g, and
  • the standard deviation SD(X) = 0.1039 g

As such, the distribution is not a standard normal distribution.

Therefore, we can conclude that the distribution is not a standard normal distribution.

Learn more about standard normal distribution here:

brainly.com/question/11876263?referrer=searchResults

7 0
3 years ago
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