F(2) = 3(2)^2 + 2(2) + 4
= 3(4) + 4 + 4
= 12 + 8
f(2) = 20
f(a+h) = 3(a+h)^2 + 2(a+h) + 4
= 3(a^2 + 2ah + h^2) + 2a + 2h + 4
f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4
C on that one which is the correct answer
-3 =-2x - 7
Add 7 to both sides
4=-2x
Divide by -2
-2 = x
Answer:
32 miles
Step-by-step explanation:
Given data
Let the total distance be x miles
Marks speed= 16miles per hour
Trisha's speed= 12 miles per hour
Trisha has covered 8 miles and has (x-8) miles to finish line
We know that
Speed= distance/time
time= distance/speed
Hence the time taken for Mark to finish is
time= x/16---------------1
The time taken for Trisha to finish is
time= (x-8)/12-----------2
equate 1 and 2 above
x/16= (x-8)/12
cross multiply
16(x-8)= 12*x
16x-128= 12x
collect like terms
16x-12x= 128
4x=128
x= 128/4
x= 32 miles
Hence they will meet at exactly 32 miles along the way
Answer?
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