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Furkat [3]
3 years ago
7

4. A school has 100 windows. On a cool day 95 of the windows were closed. Which decimal represents the amount of windows that we

re OPEN?
Mathematics
2 answers:
lions [1.4K]3 years ago
6 0
.05 or 5%. 5/100 windows were open. You put a zero before the five in decimal form to show it is in the hundredths place.
pshichka [43]3 years ago
5 0

Answer:

0.05

Step-by-step explanation:

100 windows is 1.00

95 windows is 0.95

5 = 0.05

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Decide if 6x + 2 = 2 + 6x has no solution, one solution, or infinitely many solutions
Elanso [62]

Answer:

HI!

Step-by-step explanation:

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3 years ago
X 2x+24<br> Please help me I don’t know what to do
valkas [14]

Answer:

x = 52°

Also, you can use this formula for any other angles. For example, input 90° instead of 180°. I have a feeling that you didn't understand this before. Maybe this will help.

Step-by-step explanation:

180° = x+2x+24°

180° = 3x° + 24°

180° - 24° = 3x

156° = 3x

x = 52°

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2 years ago
find the measure of the angle of elevation of the sun to the nearest degree, if a 100ft tall building casts a 150ft shadow.​
Svet_ta [14]

Answer:

33.7º

Step-by-step explanation:

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3 years ago
Solve the following problem.
Serggg [28]
<span>It costs 19.48, because $16,421.40 / 843 comes out to 19.479, and 19.479 rounds to 19.48. So the answer is B $19.48.

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8 0
3 years ago
Read 2 more answers
Given that sin theta = 1/4, 0→theta→π/2, what<br>. what is the exact value of cos 8?​
natali 33 [55]
<h3>Answer: Choice B \frac{\sqrt{15}}{4}</h3>

===========================================================

Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

Square both sides of the given equation

\sin \theta = \frac{1}{4}\\\\\sin^2 \theta = \left(\frac{1}{4}\right)^2\\\\\sin^2 \theta = \frac{1}{16}

Then use the pythagorean trig identity to get

\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\

3 0
3 years ago
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