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3 years ago

7

4. A school has 100 windows. On a cool day 95 of the windows were closed. Which decimal represents the amount of windows that we

re OPEN?

2 answers:

lions [1.4K]3 years ago

6 0

.05 or 5%. 5/100 windows were open. You put a zero before the five in decimal form to show it is in the hundredths place.

pshichka [43]3 years ago

5 0

Answer:

0.05

Step-by-step explanation:

100 windows is 1.00

95 windows is 0.95

5 = 0.05

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I am making oatmeal cookies and one batch calls for 2 3/4 cups of flour. If I am going to make 4 batches, how many cups of flour

AlekseyPX

I would say 11 cups of flour is needed for 4 batches. i am sorry if i am wrong.

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3 years ago

Read 2 more answers

A scale drawing of a park is 1 inch equal to 15 feet. What is the actual area of the park?

sesenic [268]

Answer:

Step-by-step explanation:

To get the current area of the park you must multiply by 15 the number of inches indicated on the map.

4 0

3 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Who can help to develop and solve an algebraic equation for this question?

mixer [17]

Answer:

25 mins

Step-by-step explanation:

Harpeet worked -- x mins

Aiysha worked -- 2x mins

If Aiysha worked 50 mins, Harpeet worked:

2x = 50

x = 25 mins

Thenks and mark me brainliest :))

3 0

3 years ago

When f(x)=5x^2-2x+5, evaluate f(-3)

patriot [66]

Answer:

f(-3)=56

Step-by-step explanation:

When evaluating a specific input for a function, you just plug that input in for x.

So in this case, f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(9)+6+5

f(-3)=45+6+5

f(-3)=56

8 0

3 years ago