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Vanyuwa [196]
3 years ago
15

When f(x)=5x^2-2x+5, evaluate f(-3)

Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer:

f(-3)=56

Step-by-step explanation:

When evaluating a specific input for a function, you just plug that input in for x.

So in this case, f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(9)+6+5

f(-3)=45+6+5

f(-3)=56

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The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin
irakobra [83]

Answer:

Y = 441

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

X^2 \alpha \frac{1}{\sqrt Y} \alpha M

Convert the variation to an equation; we have

X^2 = \frac{KM}{\sqrt Y}

<em>Where K is the constant of variation;</em>

When M = 27; Y = 16; X = 9, the expression becomes

9^2 = \frac{K * 27}{\sqrt{16}}

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Make K the subject of formula

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Solving for Y when M = 7 and X = 2

Recall that X^2 = \frac{KM}{\sqrt Y}

Substitute values for K, M and X

2^2 = \frac{12 * 7}{\sqrt{Y}}

4 = \frac{84}{\sqrt{Y}}

Take square of both sides

4^2 = (\frac{84}{\sqrt{Y}})^2

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Make  Y the subject of formula

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3 0
3 years ago
Please help, 8 points and brainliest answer
Darya [45]
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Just count the square, in the little is 1 and in the big is 3
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So now since we have the answer, we need to figure out if this result and 6 are equal.

6^2 = 36

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I hope this helped!
7 0
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