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denis23 [38]
4 years ago
6

PROBABILITY QUESTION!!!! PLEASE HELPPP

Mathematics
1 answer:
Alina [70]4 years ago
8 0

Answer: 7/13

Step-by-step explanation:

To do this, we find the probability of getting a black card, and getting a five but we have to subtract out the black fives.

There are 26 black cards out of the 52 cards in the set.

The are 4 fives out of the 52 cards in the set.

That would mean that 2 of the fives are black. If we didn't subtract the black fives, we would be overcounting.

Therefore we have 26/52 + 4/52 - 2/52 = 28/52 = 14/26 = 7/13

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A bucket contains one green block, one red block, and two yellow blocks. You choose one block from the bucket.
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P(green) = 1/4 p(yellow) = 2/4 p(red) = 1/4
the sum of probabilities is 1
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the sum is 1
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A drug company developed a new formula for their headache medication. To test the effectiveness of this new formula, 250 people
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Annex the bar graph that shows which improvement time is less, the new formula being more effective, with an average of 55 minutes and the average of the old formula is 75 minutes, which leads to the conclusion that the new formula is better than the previous one with a time difference of 20 minutes.

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Read 2 more answers
1. A={all even integers) under multiplication?
Paraphin [41]

Answer and Step-by-step explanation:

1-A= {all even integers} under multiplication?:

Sol: The set of positive integers under multiplication would not form because this set does not contain inverses. And no identity exists in this set. And in the case of negative even integers under multiplication, when we multiply a negative number to another negative number it becomes a positive even integer.

2-B= {all positive even integers} under averaging?:

The average of the integers from 1 to n is (n+1)/2.

Because there is only even numbers so, the formula has to doubled, this formula is used for sequences that increase by 1. So n(n+1)

There are only 1009 even integers between 2 to 2018.

2+2018=2020 and 2020/2=1010

3-C= {all odd integers} under addition:

Sol: the set of odd integers under addition does not form a set because the set of odd integers is not a closed set. Because addition of two odd numbers gives us an even number. And the other reason is that the identity element does not exist in this set. Identity for addition is zero (0) which is an even number.        

                                                                                   

4-D= {all odd integers} under multiplication:

Sol: The set of odd integers say F is not a group under multiplication (.) because the inverse of odd integers does not exist. For example an element m is belonging to odd integer group say F. its inverse (1/m) does not exist in this set. Sometimes it does not have identity.

5- E= {all prime natural numbers) under addition:

Sol: All prime natural numbers are not set under addition because when we add two prime numbers we will not get always a prime number. For example 7+3= 10

7 and 3 are prime numbers but 10 is not a prime number.

6-F= {all composite integers} under addition:

Sol: no, not all composite number under addition form a set because when we add two composite number 15 + 14 = 29, 29 is a prime number.

7-G= {all composite integers} under multiplication:

Sol: yes all composite integers form a set under multiplication because when we multiply any integer to another integer it gives composite numbers. When we multiply prime numbers it gives a composite number.

8 0
3 years ago
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