Answer:
x = 30 and y = -34
Step-by-step explanation:
Given the following functions
(1/4)^(x+y) = 256... 1
log₄(x-y) = 3.... 2
From equation 2;
x-y = 4³
x-y = 64
x = 64 + y ... 3
Substitutw 3 into 1
From 1:
(1/4)^(x+y) = 256
(1/4)^(64+y+y) = 256
(1/4)^(64+2y) = 256
Take log₄ of both sides
64+2y log₄ (1/4) = log₄256
-(64+2y) = 4log₄4
-(64+2y) = 4
64+2y = -4
2y = -4 - 64
2y = -68
y = -34
Since
x = 64 + y .
x = 64 - 34
x = 30
Hence x = 30 and y = -34
Answer:
no solution
Step-by-step explanation:
12x − 18y = 27
4x − 6y = 10
Multiply the second equation by -3 so we can eliminate x
-3(4x − 6y) = 10*-3
-12x +18y = -30
Add the first equation to this new equation
12x − 18y = 27
-12x +18y = -30
------------------------
0 = -3
This is not a true equation, so there is no solution
0 could possibly represent ground level in this situation.
Answer:
8
Step-by-step explanation:
It be wayyy to much to put 13 it would make the mean 9 8 is perfect
