-X+7x-3=0
-7(+-)√(7)^2--4(-1)(#)
(2)(#)
pass me all the picture to can help you
Answer:
Step-by-step explanation:
We need a picture of what you're talking about.
You need three non-collinear points to name a plane.
Non-collinear means "not on the same straight line". So these three points can't all lie on the same straight line. If three points do lie on the same straight line, then it is impossible to generate a single unique plane.
B. I’m pretty sure. Since the arrow is pointing towards the S which is at the beginning.
So what you do is distribute the invisible -1 in front of the second parenthasees set and add like terms
remember
x^2+3x^2=4x^2
-(3+4x-x^2)=-1(3x+4x-x^2)=-3-4x+x^2
so first distribute the negative 1
-1(-4f^2-3f+6)=4f^2+3f-6
add
12f^2-9f+15+4f+3f-6
group like terms
12f^2+4f^2-9f+3f+15-6
add
16f^2-6f+9
aswer is 16f^2-6f+9