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leva [86]
3 years ago
6

45% of the load is 27 tonnes. Find the full load.

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

the full load is 60 tonnes

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An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
erastova [34]

Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

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3 years ago
Helppp someone!! I’m giving brainliests to everyone
Annette [7]

Answer:

A.

Step-by-step explanation:

4 0
3 years ago
I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem i
Anna [14]

We know that the law of sines states that:

\frac{\sin\alpha}{a}=\frac{\sin\beta}{b}

For simplicity, let:

\beta=m\angle A_1BC

In triangle A1BC this leads to:

\begin{gathered} \frac{\sin31}{5}=\frac{\sin\beta}{6} \\ \sin\beta=\frac{6}{5}\sin31 \\ \beta=\sin^{-1}(\frac{6}{5}\sin31) \\ \beta=38.174 \end{gathered}

Therefore:

m\angle A_1BC=38.174

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:

m\angle CA_2B=180-38.174=141.826

8 0
1 year ago
the first term of an arithmetic sequence is 4 and the tenth term is 67. what is the common difference? ​
Tatiana [17]
Plss see the attachment

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3 years ago
Write an equation of a line perpendicular to the line 1/2x - 5 , passing through the point (-1 , 7)
jok3333 [9.3K]
<h3>Answer ↓</h3>

y=-2x+5

<h3>Calculations ↓</h3>

First of all we need to determine the slope of the line perpendicular to y = 1/2x - 5 .

The slopes of perpendicular lines are opposite reciprocals.

So we take 1/2 , turn it over , and change it's sign :

^1/_2\:\:\:--- > ^2/_1\:\:\:--- > 2\:\:\:--- > -2

The slope of the line perpendicular to y = 1/2x-5 is -2 .

Since we're also given a point that the line crosses , we can write the line's equation in point - slope form :

y-y₁=m(x-x₁)

y-7=-2(x-(-1)

y-7=-2(x+1)

Now convert to slope intercept :

y-7=-2x-2

add 7 on both sides :

<h3>y = -2x+5</h3>

\footnotesize\text{hope\:helpful}

7 0
2 years ago
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