Answer:
41 1/7
Step-by-step explanation:
5 1/7 x 8
Convert 5 1/7 to improper fraction
5 1/7 = 36/7
Multiply.
36 x 8
---- --
7 x 1
288/7
Simplify.
41 1/7
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hope it helps
Answer:
0
Step-by-step explanation:
since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.
in 3.4653, there is one digit to the left of the decimal point, that is the ones position
in 34.653, there are 2 numbers to the left of the decimal point, the 3 is located in the tens place
so 34.653 is greater than 3.4653
Complete Question: Which of the following is an example of the difference of two squares?
A x² − 9
B x³ − 9
C (x + 9)²
D (x − 9)²
Answer:
A. 
.
Step-by-step explanation:
An easy way to spot an expression that is a difference of two squares is to note that the first term and the second term in the expression are both perfect squares. Both terms usually have the negative sign between them.
Thus, difference of two squares takes the following form: 
.
a² and b² are perfect squares. Expanding 
will give us 
.
Therefore, an example of the difference of two squares, from the given options, is .
can be factorised as 
.
Answer:
x² + 2x + [3\x - 1]
Step-by-step explanation:
Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
1| 1 1 -2 3
↓ 1 2 0
------------------
1 2 0 3 → x² + 2x + [3\x - 1]
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder, which in this case is a 3, so what you is set the divisor underneath the remainder of 3. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², 2 becomes <em>2x</em><em>,</em><em> </em>and the remainder of 3 is set over the divisor, giving you the other factor of <em>x² + 2x + [3\x - 1]</em>.
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