Answer:
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Step-by-step explanation:
Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.
The radius of the outside edge the pool path is
= Radius of the pool + The width of the path
= (28+4) ft
= 32 ft.
To find the length of fencing, we need to find the circumference of outside the pool path.
Here r= 32 ft
The circumference of outside edge of the pool path
=

=200.96 ft.
Therefore 200.96 ft.of fencing are needed to go around the pool path.
Anything multiplied by zero is zero
The vertices of the quadrilateral ABCD lie on the sides of quadrilateral PQRS then the sum of the degree of measures of the eight indicated angles would be 360.
Answer:
( B.) 6, 1, -2 , -4
Step-by-step explanation:
A coefficient is a number multiplied by a variable. So, in this case let's take a look at the problem.
-2+6y+m-2y+8-4m
Now we have to find the numbers that have a variable next to it
which are 6,m,-2, and -4
(If you are wondering that why m is a coefficient its because it is also known as 1m)
Final answer = 6, 1, -2 , -4
Hope this helps!